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xxMikexx [17]
2 years ago
6

Faye has a bag that contains 10 red, 13 blue, 16 white, 10 green, and 11 black marbles. She pulls a marble out of the bag withou

t looking.
What is the probability Faye pulls out a white marble?

A. 1/5
B. 1/16
C. 4/11
D. 4/15
Mathematics
2 answers:
Gennadij [26K]2 years ago
6 0

Answer: D

Step-by-step explanation: To get the probability you add up all of the marbles and put the white marbles over it which should give you 16/60 or 4/15.

Rudik [331]2 years ago
5 0
D i believe it’s the correct answer
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The answer to this question is:

<span>Which form of cell division plays a key role in sexual reproduction?
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Alma is offered a job as a receptionist in a medical office. She will be paid $19.20 per hour for 37 hours per week. The office
dalvyx [7]

Answer: I believe the answer would be $42,890.80 is the total annual(yearly value) of Almas job.

Step-by-step explanation: First you need to figure out that $19.20 x 37= $710.40(hourly wage per week). Then, you need to figure out that $710.40 x 52 = $36,940.80(the weekly wage x the 52 weeks in the year). Next, add the yearly medical coverage. $5,500 + $36,940.80 = $42,440.80. Now, you know that 1/2 of the dental is going to be $350 and 1/2 of the life insurance is going to be $100. Add those to your previous balance. $42,440.80 + 350 + 100 = 42,890.80.

7 0
2 years ago
Which ordered our is a solution for this system of linear inequalities?
shutvik [7]

Answer:

D) (4,5)

Step-by-step explanation:

the ordered pair (4, 5) is the only one that, when substituted into each inequality statement, made both of them true

3 0
2 years ago
Gragh the image of the figure after a dilation with a scale factor of 1/4 centered at (5, -5) please help
svetoff [14.1K]

Answer:

See attached diagram

Step-by-step explanation:

Triangle ABC has vertices A(9,3), B(-7,-5) and C(-3,7).

The dilation with a scale factor of 1/4 centered at (5, -5) has the rule

(x,y)\rightarrow \left(\dfrac{1}{4}x+\dfrac{15}{4},\dfrac{1}{4}y-\dfrac{15}{4}\right)

Then

A(9,3)\rightarrow A'\left(\dfrac{1}{4}\cdot 9+\dfrac{15}{4},\dfrac{1}{4}\cdot 3-\dfrac{15}{4}\right)=A'(6,-3);

B(-7,-5)\rightarrow B'\left(\dfrac{1}{4}\cdot (-7)+\dfrac{15}{4},\dfrac{1}{4}\cdot (-5)-\dfrac{15}{4}\right)=B'(2,-5);

C(-3,7)\rightarrow C'\left(\dfrac{1}{4}\cdot (-3)+\dfrac{15}{4},\dfrac{1}{4}\cdot 7-\dfrac{15}{4}\right)=C'(3,-2).

6 0
2 years ago
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