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soldi70 [24.7K]
2 years ago
12

$350 at 3% for 10 years

Mathematics
2 answers:
ki77a [65]2 years ago
8 0
350(1.03)^10
350(1.3439)
$470.37
Trava [24]2 years ago
4 0
350(1+.03)^10
350(1.03)^10
350(1.3439)
$470.37
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If the circumference of a circle is 15 pie inches, then what is its diameter
Butoxors [25]

Answer:

diameter is half the value of circumference 15/2 =7.5 diameter

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2 years ago
Mrs. Jones decided to buy some pencils for her class. She bought 5 packages of pencils, and each package contained 66 pencils. T
8_murik_8 [283]
D.3 is the correct answer :)

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3 years ago
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Consider the derivation of the quadratic formula below. What is the missing radicand
Vedmedyk [2.9K]

Answer:

\frac{b^2 - 4ac}{4a^2}

Step-by-step explanation:

Given

See attachment for complete question

Required:

Complete step 6

At step 5, we have:

(x + \frac{b}{2a})^2 = \frac{b^2}{4a^2} - \frac{4ac}{4a^2}

Take LCM

(x + \frac{b}{2a})^2 = \frac{b^2 - 4ac}{4a^2}

Take square roots of both sides to get step 6

x + \frac{b}{2a} = \±\sqrt{\frac{b^2 - 4ac}{4a^2}}

Hence, the missing radicand is: \frac{b^2 - 4ac}{4a^2}

5 0
3 years ago
Let u = (5, -7) and v = (2, 1). What is u · v?<br> -2<br> 1<br> 3<br> 17
pychu [463]

Answer: B: 3

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3 0
3 years ago
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Given that (x - 1) is a factor of x4 + 2x3 - 2x - 1, what are the solutions of x4 + 2x3 - 2x - 1 = 0? A. -2, 0, 1 B. -1, 0, 1 C.
noname [10]

Answer:

<h3>D. -1, 1</h3>

Step-by-step explanation:

If x-1 is a factor of x⁴ + 2x³ - 2x - 1, then x-1 =0 is  a factor

if x-1 = 0

x = 1

To get other factors we will divide the polynomial by x-1

Find the division in the attachment

x⁴ + 2x³ - 2x - 1,/x-1 = x³ +3x²+ 3x + 1,

let x = -1 be a factor of the resulting expression

f(-1) = (-1)³ +3(-1)²+ 3(-1) + 1

f(-1) = -1 +3(1)-3 + 1

f(-1) =-1+1-3+3

f(-1) = 0

Since f(-1) =0, hence x+1 is a factor of the resulting polynomial'

Dividing x³ +3x²+ 3x + 1, by x+1 to reduce the power of the polynomial

x³ +3x²+ 3x + 1/x+1 = x²+2x+1

Factorizing x²+2x+1

= x²+2x+1

=x²+x+x+1

= x(x+1)+1(x+1)

= (x+1)(x+1)

if the function is equal to zero

x+1 = 0 and x+1 = 0

x = -1 twice

Hence the solutions to the polynomial are 1 and -1(three times)

4 0
3 years ago
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