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2 years ago

Students in a large district's two high schools are offered a "Second Breakfast' program after their first-period class.

Mathematics

1 answer:

murzikaleks [220]2 years ago

3 0

Answer:

Step-by-step explanation:

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What is the base of a parallelogram with height 6.2 meters and an area of 80.6 square meters

Diano4ka-milaya [45]

80.6 / 6.2 = 13

I think the base is 13 meters.

Formula is area = b times height

Hope this helped

4 0

3 years ago

Read 2 more answers

Solve for s.<br><br> –9s − 4 = –8s

posledela

Answer:

-s = -4

Step-by-step explanation:

-9s - 4 = -8s = -9s + 8s = -4 = -s= -4

7 0

2 years ago

The HCF of two number is 40 and their product is 52800. find their lcm

Dima020 [189]

Answer: 1320

Step-by-step explanation:

Given,

HCF of two numbers = 40

Product of two numbers = 52800

To find,

LCM of two numbers =?

Formula required,

HCF × LCM = product of two numbers

Calculation,

Using formula

→ HCF × LCM = product of two numbers

→ ( 40 ) × LCM = 52800

→ LCM = 52800 / 40

→ LCM = 1320

Therefore,

LCM of two numbers would be 1320.

4 0

2 years ago

2. Provide the next three terms in the sequence and

vivado [14]

The next three terms of -243, 81, -27, 9 is $-3,1, \frac{-1}{3}$ The given series is geometric series

<u>Solution:</u>

Given, series is -243, 81, -27, 9, …

We have to find the next three terms of the above given series.

Now, the given series can also be written as

$-243,-243 \times\left(\frac{-1}{3}\right)^{1},-243 \times\left(\frac{-1}{3}\right)^{2},-243 \times\left(\frac{-1}{3}\right)^{3}$

We can say that, above series is in Geometric Progression with first term = -243 and common ratio = $\frac{-1}{3}$

Then, next three term would be,

$-243 \times\left(\frac{-1}{3}\right)^{4},-243 \times\left(\frac{-1}{3}\right)^{5},-243 \times\left(\frac{-1}{3}\right)^{6} \rightarrow-3,1, \frac{-1}{3}$

Hence, the next three terms of given G.P series are $-3,1, \frac{-1}{3}$

6 0

2 years ago

Please please help!!! I really need help on this quarion and I keep getting it wrong :(

Marta_Voda [28]

Answer:

$f(x)=x^2+4\\g(x)=4x$

$(f+g)(x)=x^2+4+4x\\(f+g)(x)=x^2+4x+4$

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$(f-g)(x)=x^2+4-(4x)\\(f-g)(x)=x^2+4-4x\\(f-g)(x)=x^2-4x+4\\$

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$(f*g)(x)=(x^2+4)(4x)\\(f*g)(x)=4x^3+16x$

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$(\frac{f}{g})(x)= \frac{x^2+4}{4x} \\$

8 0

3 years ago