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Anna [14]
3 years ago
9

I need help on this hw

Mathematics
1 answer:
Vinil7 [7]3 years ago
7 0
Its 21 because 9+10= 21

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in a circle, a 60° sector has an area of a 36π cm^2. find the radius of the circle. round your answer to the nearest whole centi
hammer [34]
Area of circle = \frac{ \theta }{360^o}  \times \pi r^2 \\ 36 \pi = \frac{60^o}{360^o}  \times \pi r^2 \\ r^2=216 \\ r= \sqrt{216} =14.70 \ cm \\ r=15 \ cm \ to \ the \ nearest \ whole \ centimeter.
3 0
3 years ago
When plotted on a grid, the paths between four neighborhood houses form the shape of a kite as shown.
KatRina [158]

Answer:

The area of the figure is 1,000 square feet

Step-by-step explanation:

we know that

The area of the kite ABCD

is equal to

A=\frac{1}{2}[AC*BD]

where

AC and BD are the diagonals of the kite

we have

BD=50\ ft\\AC=40\ ft

substitute

A=\frac{1}{2}[40*50]=1,000\ ft^2

3 0
3 years ago
Mr Kendrick is trying to organize his year 7 class into rows for their class photograph. If Mr Kendrick wishes to organize the 2
inysia [295]
Just list the factors of 24. Those are the possible numbers of students that can be in each row.

1,2,3,4,6,8,12,24 are the possible row sizes.
5 0
3 years ago
When using fraction strips ,how do you know that 2 fractions are equivalent
Zigmanuir [339]
When the longer strip is on top and the litter strips fit perfectly under the longer one. For example, the fraction 1/3 and 3/6. One longer strip will be on the top representing 6. Then 3 litter 3s will be under that perfectly
5 0
3 years ago
Oh no! Thomas is lost in the GGBL building after an exam, and trying to get out. Thereare four identical hallways leading away f
Brums [2.3K]

Answer:

Check the explanation

Step-by-step explanation:

Since each and every one of the 4 hallways is equally likely then

P(H1)=1/4P(H2)=1/2P(H3)=1/4

Now, if he chooses H1 he escapes after 12 minutes then

E(T|H1)=12

If he chooses H2 then he wastes 10 minutes and then he is again in the same starting

position so he expects to escape in E(T) minutes, then

E(T|H2)=10+E(T)

Analogously, if he chooses H3 then he wastes 40 minutes and then he is again in the same starting

position so he expects to escape in E(T) minutes, then

E(T|H3)=40+E(T)

Therefore

E(T) = E(T|H1)P(H1) + E(T|H2)P(H2) + E(T H3)P(H3) = (12) + (E(T) +10) + (E(T) + 40) = 3+ *E(T)+5+ 10 = E(T) +18 CON A'

So we have

E(T) = E(T) + 18 E(T) = 18 E(T) = 4(18) = 72

Therefore he is expected to escape in 72 minutes

7 0
3 years ago
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