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malfutka [58]
3 years ago
13

IS 0.1369 per ounce how many is this cost to the nearest cent

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

$ 0.1369 to the nearest cent ( aka hundredth decimal place) would be $ 0.14

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given that a1=5 and a2=15 are the first two terms of a geometric sequence, determine the values of a3 and a10. Show the calculat
Alekssandra [29.7K]

a_3 is 45 and a_10 is 98415

Step-by-step explanation:

Given

a_1 = 5

a_2 = 15

First of all we have to calculate the common ratio of the sequence. The common ratio is the ratio between two consecutive terms of a geometric sequence.

So,

r=\frac{a_2}{a_1} = \frac{15}{5} = 3

The explicit formula for geometric sequence is:

a_n = a_1.r^{n-1}

Putting the value of r and a_1

a_n = 5.(3)^{n-1}

Putting n=3 in the explicit formula

a_3 =5.3^{3-1}\\= 5 * 3^2\\=5 * 9\\= 45

Putting n=10 for tenth term

a_{10} =5.3^{10-1}\\=5*3^9\\=5 * 19683\\=98415

Hence,

a_3 is 45 and a_10 is 98415

Keywords: Geometric sequence, Explicit formula

Learn more about geometric sequence at:

  • brainly.com/question/10978510
  • brainly.com/question/11007026

#LearnwithBrainly

7 0
3 years ago
1.64 written as fraction in simplest form
erastovalidia [21]
1.64 =  \frac{1.64 \times 100}{1 \times 100} = \frac{164}{100} = \frac{41\times 4}{25\times 4} = \boxed {\frac{41}{25} }
8 0
3 years ago
Can anyone please help!!!
quester [9]

Answer:

Question 9

(a) The distance, Jalaj walks in one day is 4.4 km

(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8

Question 10

(b) The difference between the largest and smallest areas is 2,400 m²

Step-by-step explanation:

Question 9

(a) The distance Jalaj walks in 5 days = 22 km

Whereby Jalaj walks equal distance every day, we have;

The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day

The distance, Jalaj walks in one day = 4.4 km

(b) The amount he raises for every kilometer he walks = $1.60

The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60  = $8

Question 10

(b) The given side length of the square = 120 meters to the nearest 10 meters

Therefore;

The maximum dimension for the side length of the square = 120 + 10/2 = 125

The largest possible area of the square, A_l = 125 m × 125 m = 15,625 m²

The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m

The smallest possible area of the square, A_s = 115 m × 115 m = 13,225 m².

The difference between the largest and smallest areas, A_l - A_s = 15,625 - 13,225 = 2,400 m².

8 0
2 years ago
I GIVE BRAINLIEST!!!
Doss [256]

Answer: I'm sorry I don't know but il try and calculate the answer for you

Step-by-step explanation:

8 0
3 years ago
Bob decided to give up a full-time salary of $45000 a year to go to school for 4 years. The total cost of going to school will n
den301095 [7]

Answer:

Step-by-step explanation:

Semester Costs = 8*2858 =                     22864

Books / semester= 8 * 391 =                        <u>3128</u>

Total                                                            25992

If he wants to repay all this in six years the answer would be

45000 + 25992/6 = 45000 + 4332 = 49332

3 0
3 years ago
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