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torisob [31]
3 years ago
9

4^2-6(2^x)-16=0solve for x

Mathematics
1 answer:
ahrayia [7]3 years ago
8 0
Assuming that   <span>4^2-6(2^x)-16=0   is correct, we can rearrange it as:

</span><span>-6(2^x) + 4^2 - 16=0

Are you sure it's not   </span>6(2^x) + 4^2 - 16=0  ?

If   6(2^x) + 4^2 - 16=0    is correct, then

6(2^x) + 4^2 - 16=16 - 16 = 0, that is,   6(2^x) = 0.  Then x = 0 (answer)
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Multiply. Express your answer in simplest form.
kodGreya [7K]

Step-by-step explanation:

1.) First, you need to take the whole numbers (9 and 1) and set them aside.

2.) Multiply the numerators from each fraction by one another. The numerators are the numbers on the top of the fraction. (Whatever you get on that will be the numerator of the answer!)

3.) Multiply the denominators by each other as well. The denominators are the numbers on the bottom. This will be the denominator of your answer.

4.) Now, you need to multiply your whole numbers (9 and 1) together.

5.) Then, simplify or reduce your answer. (this can't be simplified, as it is already in its simplest form)

Your answer will be 9 1/66.

Your work should look like this in the end:

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3 years ago
I need help its7th grade work
storchak [24]
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3 years ago
The graph shows the amount of money paid when purchasing bags of peanuts at the zoo: What is the constant of proportionality? (4
jolli1 [7]

Answer:

The constant of proportionality is equal to 4

Step-by-step explanation:

The picture of the question in the attached figure

Let

y ----> the total cost in dollars

x ----> the number of bags of peanuts

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

To find out the constant of proportionality, we need to take one point from the graph

take the point (1,4)

Find the value of k

k=\frac{y}{x}

substitute the value of x and the value of y

k=\frac{4}{1}=\$4\ per bag

6 0
3 years ago
This graph shows a proportional relationship.
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2 years ago
Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.
Setler79 [48]

Answer:

Therefore values of a and b are

a=3\ and\ b = 2

Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

(x-a)^{2}=b

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9

Adding half coefficient of X square on both the side we get

x^{2}-6x+9=-7+9=2 ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}

Substituting in equation 1 we get

(x-3)^{2}=2

Which is in the form of

(x-a)^{2}=b

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

4 0
3 years ago
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