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torisob [31]
3 years ago
9

4^2-6(2^x)-16=0solve for x

Mathematics
1 answer:
ahrayia [7]3 years ago
8 0
Assuming that   <span>4^2-6(2^x)-16=0   is correct, we can rearrange it as:

</span><span>-6(2^x) + 4^2 - 16=0

Are you sure it's not   </span>6(2^x) + 4^2 - 16=0  ?

If   6(2^x) + 4^2 - 16=0    is correct, then

6(2^x) + 4^2 - 16=16 - 16 = 0, that is,   6(2^x) = 0.  Then x = 0 (answer)
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Step-by-step explanation:

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Let $P$ and $Q$ be constants. The graphs of the lines $x + 5y = 7$ and $15x + Py = Q$ are perpendicular and intersect at the poi
Marta_Voda [28]

Answer:

<em>(-3, -129)</em>

<em></em>

Step-by-step explanation:

Given

Two lines:

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Solution:

The two lines intersect at (-8,3).

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7 0
3 years ago
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Step-by-step explanation:

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2.47 is 2.47% of 100
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3 years ago
Read 2 more answers
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Bas_tet [7]

Answer:

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Step-by-step explanation:

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base = 5.6 cm

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3 years ago
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