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3 years ago

9

4^2-6(2^x)-16=0solve for x

1 answer:

ahrayia [7]3 years ago

8 0

Assuming that <span>4^2-6(2^x)-16=0 is correct, we can rearrange it as:

</span><span>-6(2^x) + 4^2 - 16=0

Are you sure it's not </span>6(2^x) + 4^2 - 16=0 ?

If 6(2^x) + 4^2 - 16=0 is correct, then

6(2^x) + 4^2 - 16=16 - 16 = 0, that is, 6(2^x) = 0. Then x = 0 (answer)

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∠A and ∠B are adjacent. The sum of their measures is 92∘. ∠A measures (2x+5)∘. ∠B is three times the size of ∠A.

Ilia_Sergeevich [38]

Answer:

Equation: 2x + 5 + 6x + 15 = 92

Solution: x = 9

m∠A =23° m∠B = 69°

Step-by-step explanation:

measure of ∠B = 3(2x + 5) = 6x + 15

The sum of the angles = 92 = 2x + 5 + 6x + 15

92 = 8x + 20

72 = 8x

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m∠A = 2(9) + 5 = 18 + 5 = 23

m∠B = 6(9) + 15 = 54 + 15 = 69

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Answer:

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2 years ago

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zheka24 [161]

Step-by-step explanation:

9.1k=64.7

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9.1(7)=64.7

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3 years ago

Read 2 more answers

Divide x5+15x4+54x3−25x2−75x−34 by x+8.

Wittaler [7]

we are given

$x^5+15x^4+54x^3-25x^2-75x-34$

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we can use long division

so, we will get

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we can also write it as

$\frac{x^5+15x^4+54x^3-25x^2-75x-34 }{x+8}=(x^4+7x^3-2x^2 -9x-3)-\frac{10}{x+8}$ ..............Answer

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3 years ago