Given:
The equation of the curve is:
To find:
The gradient (slope) of the given curve at point (2,7).
Solution:
We have,
Differentiate the given equation with respect to x.
Now we need to find the value of this derivative at (2,7).
Therefore, the gradient (slope) of the given curve at point (2,7) is 19.
we have point (-6, - 1)
Now we will put these points in each equation,
y = 4x +23
put x = -6 and y = -1
-1 = 4 (-6) +23
-1 = -24 + 23
-1 = -1
LHS = RHS, so this equation has (-6 , -1) as solution.
y = 6x
put x = -6 and y = -1
-1 = 6 (-6)
-1 not= -36
LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,
y = 3x - 5
put x = -6 and y = -1
-1 = 3 (-6) - 5
-1 = -18 - 5
-1 not= -23
LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,
y= 1/6 x
put x = -6 and y = -1
-1 = -6/6
-1 = -1
LHS = RHS, so (-6 , -1) is a solution for that equation,
Answer:
72
Step-by-step explanation:
180-78-30=72
Answer:W=5x15
HTH
Step-by-step explanation:
Answer: (2,0),(−2,0)
Step-by-step explanation:
