Answer:

Explanation:
Amend the typos for better understanding:
<em />
- <em>On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population increases by a factor of 5 every 2 days, and can be modeled by a function, L, which depends on the amount of time, t (in days). Before the first day of spring, there were 7600 locusts in the population. Write a function that models the locust population t days since the first day of spring.</em>
<em />
<h2>Solution</h2>
A function that grows with a constant factor is modeled by an exponential function of the kind:

Where A is the initial value, B is the constant growing factor, and x is the number of times the growing factor applies.
Since the population increases by a factor of 5 every 2 days, the power x of the exponential function is t/2, and the factor B is 5.
The initial popultaion A is 7600.
Thus, the function that models the locust population t days since the first day of spring is:

Answer:
Step-by-step explanation:
Consider curl
where
is a scalar function and F is a vector function

i j k



Answer:
maximum
vertex at (-1,1)
axis of symm: x = -1
2 solutions
(-2,0) and (0,0)
Step-by-step explanation:
Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
Answer:
69 tht is the answer if you work it out
Step-by-step explanation: