Answer:
y=(y\x - 10j\x) x+j•10
Step-by-step explanation:
its up there
a. By definition of conditional probability,
P(C | D) = P(C and D) / P(D) ==> P(C and D) = 0.3
b. C and D are mutually exclusive if P(C and D) = 0, but this is clearly not the case, so no.
c. C and D are independent if P(C and D) = P(C) P(D). But P(C) P(D) = 0.2 ≠ 0.3, so no.
d. Using the inclusion/exclusion principle, we have
P(C or D) = P(C) + P(D) - P(C and D) ==> P(C or D) = 0.6
e. Using the definition of conditional probability again, we have
P(D | C) = P(C and D) / P(C) ==> P(D | C) = 0.75
Answer:
Mark C.
Step-by-step explanation:
If there are 27 students in both classes, it's logicial to multiply both classes by two to get the total students.
Since the <em>S</em> stands for the students absent, that should come after the brackets.
297 is the sum of F and 211
297 = f+211
Answer:
3x^2 + 7xy + 5
Step-by-step explanation:
