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marishachu [46]
3 years ago
15

Which categories does 11 belong in

Mathematics
1 answer:
sergeinik [125]3 years ago
3 0

Answer:

Odd numbers, double digits

Step-by-step explanation:

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Which verbal expression best represents the algebraic expression
suter [353]

Answer:

13x

Step-by-step explanation:

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3 years ago
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Take a better pic I can’t seee
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Theequationforlinegcanbewrittenas y = –9 4 x − 1 . Line h , whichisperpendiculartoline g , includesthepoint (10, 4) . What isthe
KATRIN_1 [288]

Answer:

y-4 = 4/9(x-10)

Step-by-step explanation:

Given the equation of the line g to be y = -9/4 x - 1.

To find the equation of a line h perpendicular to this line, the following steps must be taken;

First find the slope of the known line g

The standard equation of a line is y = mx+c where

m is the slope

c is the intercept

Comparing this equation with the given equation y = -9/4 x -1, it can be seen that the slope of the line g is -9/4

Next is to find the slope of the line h

Since the line g is perpendicular to h, then the product of their slope will be -1 i.e mh*mg = -1

mh = -1.mg

mh = -1/(-9/4)

mh = -1*-4/9

mh = 4/9

Hence the slope of the line h is 4/9

Find the intercept of line h

To get this, you will substitute the slope m and the point into the equation y = mx+c

m = 4/9

(x,y) = (10,4)

4 = 4/9(10) + c

4 = 40/9 + c

c = 4-40/9

c = (36-40)/9

c = -4/9

Hence the intercept of the line h is -4/9

Finally, find the equation of the line h in slope-intercept form

The slope-intercept form of a line is expressed as y = mx+c

y-y0 = m(x-x0)

Given

m = -4/9

x0 = 10

y0 = 4

Substitute:

y-4 = 4/9(x-10)

Hence the equation in slope-intercept form is y-4 = 4/9(x-10)

7 0
3 years ago
Study the example on the right to help you complete the problem below. please help!:(
Inga [223]

Answer : The equation for 'h' is h=\frac{2A}{b}

Step-by-step explanation :

The given equation is:

A=\frac{1}{2}bh

Now we have to determine the equation for 'h'.

A=\frac{1}{2}bh

Multiplying the equation by 2.

2\times A=2\times \frac{1}{2}\times bh

on simplifying, we get:

2\times A=bh

Dividing the equation by 'b'.

\frac{2\times A}{b}=\frac{bh}{b}

\frac{2\times A}{b}=h

or,

h=\frac{2A}{b}

Therefore, the equation for 'h' is h=\frac{2A}{b}

3 0
3 years ago
Andrew is 3 times his son’s age. 10 years ago, he was 5 times his son’s age. What are their present ages? Show your work.
PSYCHO15rus [73]
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

We will be using simultaneous equations to solve this problem.

Let's establish the two equations we will be using to solve the problem.

Let Andrew's current age = a

Let Andrew's son's current age = s

Equation No. 1 -

a = 3s

Equation No. 2 -

a - 10 = 5s

To begin with, we will substitute the value of ( a ) from the first equation into the second equation to solve for ( s ).

Equation No. 2 -

a - 10 = 5s

( 3s ) - 10 = 5s

3s - 5s = 10

- 2s = 10

s = 10 / - 2

s = - 5

Next we will substitute the value of ( s ) from the second equation into the first equation to solve for ( a ).

Equation No. 1 -

a = 3s

a = 3 ( - 5 )

a = - 15

FINAL ANSWER:

Therefore, the present age of Andrew is - 15 and the present age of Andrew's son's is - 5.

It isn't possible for someone to be negative years old, but this is the answer that I ibtained from the equations.

Hope this helps! :)
Have a lovely day! <3
6 0
3 years ago
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