I believe it's A. Day 1 decreased by half from 8 would be 4. Day 2 decreased by half from 4 would be 2. Day 3 decreased by half from 2 would be 1. then .5 would be decrease by. 25, which would be .75. I hope that makes sense:)
Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single (
) - p is the proportion of elementary teachers who were single (
)
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)
Answer:
The solution is (4, 0)
Step-by-step explanation:
Using Linear combination method to solve:

Since "e" have the same coefficient in both equation with opposite operator; we will add.

Divide both side by coefficient of d which is 3

Since d = 4; put 'd' into any of the equation to get 'e'

Therefore, the solution is (4, 0)
Babysitting for 8 hours and making $72.00 because of a better/greater amount of money
We are given

we know that

so, we get
opposite =7
adjacent=24
now, we can find hypotenuse


now, we can draw triangle and then switch vertices accordingly
we can find cos(B) using second triangle

In second triangle:
adjacent=7
hypotenuse =25
so, we get
................Answer