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2 years ago

Which categories does 11 belong in

Mathematics

1 answer:

sergeinik [125]2 years ago

3 0

Answer:

Odd numbers, double digits

Step-by-step explanation:

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X-2y = 6 Зх — бу = 18 Solve using elimination

nalin [4]

Answer:

x-2y = 6

x=6+2y....,.........1

Зх — бу = 18.............2

putting the value of x in ..2

3(6+2y)-6y=18

18+6y-6y=18

0=o

8 0

2 years ago

which of the following expressions does not contain any like terms? a. 2x^2+3x-4x+2 b. xy+yz-17 c. x^3+x^2-2x-x^2 d. 14+8+y

solniwko [45]

Answer : B

The expression xy+yz-17 do not contain any like terms

I hope that's help !

4 0

3 years ago

8. If the measure of one side of a square is increased by 2 centimeters and the measure of

GalinKa [24]

Answer:

6 cm

Step-by-step explanation:

If the original side length is x, then the modified square has an area of ...

A = LW

32 = (x +2)(x -2) = x^2 -4

36 = x^2 . . . . . . . . add 4

6 = x . . . . . . . . . . take the square root

The original figure has a side length of 6 cm.

Check

The modified figure is 8 cm by 4 cm = 32 cm^2.

8 0

2 years ago

Graph and write the solution: Y= x - 4 Y= 1/3x - 2

Reika [66]

Answer:

1. x=4

2. x=6

Step-by-step explanation:

I've attached the graphs here:

Clearly, the solution for first one is(Reminder: the solution is the x-intercepts, when y is zero):

x=4

And the second is:

x=6

Hope this helps!

Mark brainliest if you think I helped! Would really appreciate!

6 0

2 years ago

Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil

andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that $p = 0.26$

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that $n = 5$

4 failures, so 1 success, and we have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898$

0.3898 = 38.98% probability that there will be 4 failures

4 0

2 years ago