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denis23 [38]
3 years ago
9

PLZZZ HELP

Computers and Technology
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

C is object-oriented design

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Real numbers which, when squared, become smaller than the original number."
8_murik_8 [283]
Those would be numbers below 1.

Explanation:
.5•.5 = .25
-2•-2 = -4
Hope this helps!
Also consider giving me brainliest.
7 0
2 years ago
Which domain indicated the website is sponsored by the university or college
Pie

The answer is edu. Hope this helps.


3 0
3 years ago
Write a program that takes three numbers as input from the user, and prints the largest.
balandron [24]

Answer:

I'll be using python:

__________________________

a=int(input("Enter a number :"))

b=int(input("Enter another number :"))

c=int(input("Enter last number :"))

lis=[a,b,c]

sort=sorted(lis)

print("The largest number is:", sort[1])

___________________________

8 0
3 years ago
Create a method called nicknames that passes an array as a parameter. Inside the method initialize it to hold 5 names of your ch
Gre4nikov [31]
<h2>Answer:</h2>

    //======METHOD DECLARATION=========//          

    //method name: nicknames                                          

    //method return type: void                                            

    //method parameter: an array reference                    

    public static void nicknames(String [] names){      

       //initialize the array with 5 random names              

       names = new String[] {"John", "Doe", "Brian", "Loveth", "Chris"};

       //using an enhanced for loop, print out the elements in the array

       for(String n: names){

           System.out.print(n + " ");

       }

       

    }

<h2>Explanation:</h2>

The program is written in Java. It contains comments explaining important parts of the code. Kindly go through these comments.

A few things to note.

i. Since the method does not return any value, its return type is <em>void</em>

ii. The method is made public so that it can be accessible anywhere in and out of the class the uses it.

iii. The method is made static since it will most probably be called in the static main method (at least for testing in this case)

iv. The method receives an array of type <em>String </em>as parameter since the names to be stored are of type <em>String</em>.

v. The format of initializing an array manually should follow as shown on line 7. The <em>new</em> keyword followed by the array type (String), followed by the square brackets ([]) are all important.

vi. An enhanced for loop (lines 9 - 11) is a shorthand way of writing a for loop. The format is as follows;

=> The keyword <em>for</em>

=> followed by an opening parenthesis

=> followed by the type of each of the elements in the array. Type String in this case.

=> followed by a variable name. This holds an element per cycle of the loop.

=> followed by a column

=> followed by the array

=> followed by the closing parenthesis.

=> followed by a pair of curly parentheses serving as a block containing the  code to be executed in every cycle of the loop. In this case, the array elements, each held in turn by variable n, will be printed followed by a space.

A complete code and sample output for testing purposes are shown as follows:

==================================================

public class Tester{

    //The main method

    public static void main(String []args){

       

       String [] names = new String[5];

       nicknames(names);

    }

   

  //The nicknames method

    public static void nicknames(String [] names){

       names = new String[] {"John", "Doe", "Brian", "Loveth", "Chris"};

       for(String n: names){

           System.out.print(n + " ");

       }

       

    }

}

==================================================

<h2>Output:</h2>

John Doe Brian Loveth Chris

<em>NB: To run this program, copy the complete code, paste in an IDE or editor and save as Tester.java</em>

6 0
3 years ago
The strength of gravity on the Moon is 1.6
sergeinik [125]

Answer:

Mass = 80kg

Explanation:

Given

On Earth

Mass = 80kg

On the moon

g = 1.6N/kg

Required

The astronaut's mass on the moon

The mass of an object do not change base on location

So, if the mass of the astronaut is 80kg on earth, it will be 80 kg on the moon.

Hence:

Mass = 80kg

6 0
3 years ago
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