Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that
74% of student are taking an English class
This means that
70% of students are taking both
This means that
Find the probability that a randomly selected student is taking a math class or an English class.
This is , which is given by:
So
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Hindi ko slam yan sorry ha
Answer:
5/7
Step-by-step explanation:
2 1/7 x 1/3
= 15/7 × 1/3
= 15 × 1/7 × 3
= 15/21
= 15 ÷ 3/21 ÷ 3
= 5/7
Answer:
slope = 0
y intercept = -5
Step-by-step explanation:
y= -5 is a horizontal line
horizontal lines have a slope of 0
it crosses the x axis at y=-5
Answer:
(2,7)
Step-by-step explanation:
We know that the change in x from A to M is -2, and the change in y is 1 -- we can simply double that and add that to A to get B, as M is halfway between A and B. Thus, (6,5)+(-4,2)=(2,7) as the coordinates of B