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Anuta_ua [19.1K]
3 years ago
7

John had 84 dollars, and his brother Fred owed 12 dollars to his friend. John gave his brother some money. Fred paid his debt an

d now both of them has the same amount left. How much money did John give Fred?
Mathematics
1 answer:
Alja [10]3 years ago
4 0

Answer:

John have $36 and he should give $48 to his brother for both to have equal money.

Step-by-step explanation:

Given that,

amount of money John have = $84

amount of money John's brother owed to her friend = $12

$12 of the $84 is going to his brother's friend, that leaves $72 for John and his brother.

If they are to finish with the same amount, then each should have half of the John's money after he paid $12

So,

72/2

= 36 each

but since John's brother have to give 12 rupees in debt so

36+12

= $48

So John should have $36 and he should give $48 to his brother.

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Answer:

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Step-by-step explanation:

This is obvious the correct answer, considering that the denominator can NEVER equal zero.

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Paul got 15 out of 20 questions correct on his test. What percent of the questions did Paul get correct?
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75%

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Help!! Which of the following uses the reciprocal property to rewrite 12/x-3 = 20/x+3?
loris [4]

<em><u>The reciprocal property is:</u></em>

\frac{x - 3}{12} = \frac{x + 3}{20}

<em><u>Solution:</u></em>

Given that,

\frac{12}{x - 3} = \frac{20}{x + 3}

<em><u>The reciprocal property is given as:</u></em>

The reciprocal of a fraction is the numerator and denominator switched

\frac{a}{b} = \frac{c}{d}\\\\Then\\\\\frac{b}{a} = \frac{d}{c}

Therefore,

\frac{12}{x - 3} = \frac{20}{x + 3}

By reciprocal property,

Switch the numerator and denominator of right side fraction as well as left side fraction

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\frac{x - 3}{12} = \frac{x + 3}{20}

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Answer:

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Step-by-step explanation:

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Find the critical numbers and the intervals on which the function f(x)=9x5−3x3+6f(x)=9x5−3x3+6 is increasing or decreasing. Use
Ierofanga [76]

Answer:

x = (0, -√(3/5), √(3/5)) are the critical points.

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The function is increasing in the interval

(−∞, -√(3/5)) U (√(3/5), ∞)

And decreasing in the interval

(-√(3/5), 0) U (0, √(3/5))

Step-by-step explanation:

Given the function

f(x) = 9x^5 - 3x³ + 6

First of all, take the first derivative of this, to have

f'(x) = 45x^4 - 27x²

The critical point are the points where the first derivative vanishes, that is

f'(x) = 0

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45x^4 - 27x² = 0

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So, x = (0, -√(3/5), √(3/5)) are the critical points.

Local maximum is when f'(x) > 0, this is √(3/5) in this case,

and local minimum is when f'(x) < 0, this is -√(3/5) in this case.

Now, we need to test for the various intervals to determine where the function increases and decreases.

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(-√(3/5), 0):

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= -18/5 < 0. Decreasing

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f'(√(1/5)) = 45(√(1/5))^4 - 9(√(1/5))² = -18/5 < 0. Decreasing

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(−∞, -√(3/5)) U (√(3/5), ∞)

And decreasing in the interval

(-√(3/5), 0) U (0, √(3/5))

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