The question is asking you to find the measure of YZ's arc.
The arc of a circle is found by finding the central angle. In this case, that's angle YCZ. Remember that a circle's total degrees is 360. Since the angle that you are trying to find is 16% of the circle, you need to find 16% of 360.
360*0.16 = 57.6
The measure of arc YZ is 57.6 degrees.
<span>1.6-g when g=1.2
= 1.6 - 1.2
= 0.4
</span><span>1/2 k when k =2/3
1/2 (2/3)
= 1/3
hope it helps</span>
Answer:
Angle 5 = 122
Step-by-step explanation:
Assume EB and AD intersect each other at point C
As this is the circle, four points A,B,D,E are all on the circle, so that we have:
+) m∠EBD = 1/2 measure of arc ED (small arc)
=> m∠EBD = 1/2 . 66 = 33 degree
=> m∠CBD = 33
+) m∠ADB = 1/2 measure of arc AB (small arc)
=>m∠ADB = 1/2 . 50 = 25 degree
=>m∠CDB = 25 degree
In the triangle CDB, we have total measure of three internal angles is 180 degree
=> Angle 5 + m∠CDB + m∠CBD = 180
=> Angle 5 + 25 + 33 = 180
=> Angle 5 = 180 -25 - 33 = 122 degree
X=2
you multiply by 8 on both sides. so that your equation now looks like x-2=0
then you will add by 2 on both sides.
x=2
The answer is −10d4+17d2s−6s2
