set f(x) equal to y
y = 19/ x^3
swap x and y
x = 19/y^3
make y the subject
xy^3 = 19
y^3 = 19/x
![y = \sqrt[3]{ \frac{19}{x} }](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B19%7D%7Bx%7D%20%7D%20)
then just replace y with f^-1(x)
![f(x) = \sqrt[3]{ \frac{19}{x} }](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B19%7D%7Bx%7D%20%7D%20)
hope this helped! have a good day ~ •lipika•
Answer:
21 is the answer my guy
Step-by-step explanation:
7 times 3 is 21
Answer:
t would be steeper
Step-by-step explanation:
Answer: the y-intercept is -7
Step-by-step explanation: Rewrite the equation in slopr intercept form and simplify:
2x-5y=35 Subtract 2x from both sides
-5y = -2x + 35 Divide both sides by -5 to isolate y
y = 2x/5 -7
Answer:
y=6
Step-by-step explanation: