Answer:
The average angle at which the airplane must descend for landing is 21°
Step-by-step explanation:
Here, we have question related to angle of elevation and depression
The height of the airplane be, y = 10,000 ft
The Location of the airport is, x = 50 miles = 26400 ft
Therefore,
we have,
Let the average angle be θ
Therefore,

The opposite to the angle of descent is the height and the adjacent is the distance of the airport away from the airplane
Therefore, tan θ = 
Therefore, the average angle θ = tan⁻¹ 0.379 = 20.746 ° ≈ 21°.
Answer:
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Step-by-step explanation:
b
We are given:

There seems to be nothing I can do to simplify this equation. However, I can factor out an
since they both have at least an
. Here is what we get:

This is in the simplest form I can get into. I cannot do anything more to simplify this expression. This is your final answer.
f= the original amount of people, a steady growth throughout the years
t=time
In 1955 the population was 12 thousand. Compared to the current population of 12.36 thousand, the population then was roughly 77%.