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2 years ago

Can you help me on this one

Mathematics

1 answer:

Annette [7]2 years ago

3 0

Answer: B. Line AC is congruent to line BD

Step-by-step explanation:

The Hypotenuse-Leg Theorem states that two right triangles are congruent if and only if the hypotenuse and a leg of one right triangle are congruent to the hypotenuse and a leg of the other right triangle.

Since they both share Leg DC, their hypotenuse should be congruent to use this proof.

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A plane can fly 305 miles downwind in the same amount of time as it can travel 215 miles upwind. Find the velocity of the wind i

son4ous [18]

Answer:

We can compute this in 2 ways:

305 downwind - 260 still air = 45 mph wind velocity

260 still air - 215 downwind = 45 mph wind velocity

Step-by-step explanation:

5 0

2 years ago

Type in the value of y.<br><br><br><br> If x = 7, then y =

Mila [183]

<h3>Answer: 8</h3>

Explanation:

The rule says "whatever x is, add 1 to it to get y"

So for instance, if x = 3, then y = x+1 = 3+1 = 4

Now if x = 7, then y = x+1 = 7+1 = 8

3 0

2 years ago

Read 2 more answers

Find the length of the missing side. If necessary, round to the nearest tenth.

svetlana [45]

The pythagorean theorem states that the sum of the squares of two legs of a right triangle is equivalent to the hypotenuse.

So:

35^2 + b^2 = 40^2

1225 + b^2 = 1600

b^2 = 375

b = $\sqrt{375}$

b = 19.3649

<u>The missing side's length rounded to the nearest tenth is Option C, 19.4</u>

3 0

3 years ago

Oranges were on sale for $0.45 per pound. Leo bought 12.6 pounds. Which expression shows how to determine the total cost of the

Rufina [12.5K]

Answer:

0.45 x 12.6= X

Step-by-step explanation:

X= 5.67

6 0

2 years ago

Read 2 more answers

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin

vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

$F =450N$

$x_1 = 30cm$

$x_2 = 60cm$

Required

The work done

First, we calculate the spring constant (k)

$F = kx_1$

$450N = k *30cm$

$k = \frac{450N}{30cm}$

$k =15N/cm$

So:

$F = kx_1$

$F(x) = 15x$

The work done using Hooke's law is:

$W =\int\limits^a_b {F(x)} \, dx$

This gives:

$W =\int\limits^{60}_{30} {15x} \, dx$

Rewrite as:

$W =15\int\limits^{60}_{30} {x} \, dx$

Integrate

$W =15 \frac{x^2}{2}|\limits^{60}_{30}$

This gives:

$W =15 *\frac{60^2 - 30^2}{2}$

$W =15 *\frac{2700}{2}$

$W =15 *1350$

$W =20250N-cm$

Convert to Nm

$W =\frac{20250Nm}{100}$

$W =202.50Nm$

7 0

2 years ago