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3 years ago

Find the value of X 11, 20, x, 7 Mean = 14 x = _____

Mathematics

2 answers:

s344n2d4d5 [400]3 years ago

8 0

11+20+7+x= (4)(14)
38+x=56
-38+x=56-38
X=18

kap26 [50]3 years ago

6 0

Answer:

Step-by-step explanation:

because their is 4 numbers multiply 14 by 4 14*4=56

then minus the three numbers you have to get 18 56-11-20-7=18

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When it comes to reducing that’s where I start having trouble for example 10/13x1/15= 10/65 but 10/65 not in lowest terms so I h

arlik [135]

Answer:

Step-by-step explanation:

Let's use your example as a starting point. Determine whether the same number will divide each 10 and 65 evenly. In this case, the answer is yes, and the number is 5. 10/5 = 2, and 65/5 = 13. Thus, the fraction in lowest terms is 2/13.

6 0

3 years ago

Which is equivalent to this expression? 2/150 + 3/75

Lesechka [4]

Answer:

Step-by-step explanation:

$\frac{2}{150}$ First reduce this to lowest term

$\frac{2}{150}=\frac{1}{75}\\\\\frac{2}{150}+\frac{3}{75}=\frac{1}{75}+\frac{3}{75}\\\\=\frac{1+3}{75}=\frac{4}{75}\\$

7 0

3 years ago

Ámala caught 54 fishes, she released 5/6 how many she keep

matrenka [14]

9 fish (:
5/6 of 54 is 45, so you would need to subtract 45 from 54, which is 9.
I hope you find this useful, and, if so, please mark as brainliest :P
Good luck!

4 0

3 years ago

Read 2 more answers

What number must be added to the expression below to complete the square? x² - 18x

kiruha [24]

Answer:

$\boxed {\boxed {\sf 81}}$

Step-by-step explanation:

The standard form of a quadratic is:

$ax^2+bx+c$

To complete the square, the a (leading coefficient) must be 1 and there can only be terms with variables on one side.

The expression given:

$x^2-18x$

follows these rules. Next, we divide the b (linear coefficient) by 2, then square it. Basically:

$(\frac{b}{2})^2$

The b in the expression is -18.

$(\frac{-18}{2})^2$

$(-9)^2= -9*-9= 81$

This is the number that is added.

5 0

3 years ago

(Geometry) The answers are x = 15 and y = 9 but I don't know how. Help me understand this

Kryger [21]

Check the picture below.

$\bf \stackrel{\measuredangle DAC}{4y+2x}~~=~~\stackrel{\measuredangle BCA}{9y-x}\implies 2x=5y-x\implies 3x=5y\implies \boxed{x=\cfrac{5y}{3}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\measuredangle DAB}{[(4y+2x)+35]}~~+~~\stackrel{\measuredangle ADC}{5x+4}~~=~~180\implies 4y+2x+5x+39 = 180 \\\\\\ 4y+7x+39=180\implies 4y+7x=141\implies \stackrel{\textit{substituting "x"}}{4y+7\left( \boxed{\cfrac{5y}{3}} \right)} = 141$

$\bf 4y+\cfrac{35y}{3}=141\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3\left( 4y+\cfrac{35y}{3} \right)=3(141)}\implies 12y+35y=423 \\\\\\ 47y=423\implies y=\cfrac{423}{47}\implies \blacktriangleright y = 9 \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that}}{x=\cfrac{5y}{3}}\implies x = \cfrac{5(9)}{3}\implies \blacktriangleright x = 15 \blacktriangleleft$

4 0

3 years ago