Answer:
A: Cu; B: Mg; C: Mg + Cu²⁺ ⟶ Mg²⁺ + Cu
Explanation:
The left-hand side of the cell diagram is where oxidation occurs (the anode).
Mg ⟶ Mg²⁺ + 2e⁻
So, Mg is the anode.
The right-hand side of the cell diagram is where reduction occurs (the cathode)
Cu²⁺ + 2e⁻ ⟶ Cu
As the copper ions hit the copper cathode, they remove electrons from the metal and become copper atoms. Since the metal has lost electrons, Cu is the positive electrode.
To get the overall reaction, we add the two half-reactions,
Mg ⟶ Mg²⁺ + 2e⁻
<u>Cu²⁺ + 2e⁻ ⟶ Cu </u>
Mg + Cu²⁺ ⟶ Mg²⁺ + Cu
Answer: I don’t know lol
Explanation: I am so sorry I thought this was easy
The practical work inside the lab includes lab equipments, chemicals, and the practical outside a laboratory is more about conservation of nature and practicals include natural things in their living areas.
What are lab practicals?
Practicals are set up stations with lab equipments and chemicals and where students learn practical of the theoretical statements.
The exams of practicals are done to test the leaning of chemistry of the students.
Thus, the practical work inside the lab includes lab equipments, chemicals, and the practical outside a laboratory is more about conservation of nature and practicals include natural things in their living areas.
Learn more about lab practicals
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Answer:
6.61%
Explanation:
You know that the equation to find the mass percent is "mass(%) = (mass of solute)/(mass of solution)". Now, to find the mass of solute (NaCl), we know that it is given by 1.2 moles/liter and its molecular weight is 58.44 g/mol, so if you multiply those quantities the result will be 70.128 g/liter. And now we need to calculate the mass of solution, that is given by the density of solution multiplied by the volume (1000ml). Finally we just need to divide the mass of solute (70.128) by the mass of solution (1060) and multiply it by 100.
The correct answer is voltage.
According to ohm's law,
V = IR, where V is the potential difference between two points(voltage), I is the electricity, R is resistance.
If the resistance in the electrical conductor is kept constant then the current in the circuit can be increased by increasing the voltage.