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LenaWriter [7]
2 years ago
13

Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:

Chemistry
1 answer:
antoniya [11.8K]2 years ago
8 0

The electron group arrangement of PH₃ is tetrahedral. The molecular shape is a Trigonal pyramid, and the bond angle is 93°.

<h3>What is the bond angle?</h3>

The angle between the atoms in a compound is known as the bond angle. The degree of the binding angle is specified. There is also the bond length. It is the separation between the two atoms' nuclei.

The bond angle between the atoms of phosphine is 93°. It has one lone pair. The central atom is covered with 4 atoms.

Thus, the electron-group arrangement of phosphine is tetrahedral. The molecular geometry or shape is a trigonal pyramid. The bond angle is 93°.

To learn more about bond angles, refer to the link:

brainly.com/question/1851495

#SPJ4

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The formation of ammonia is represented by the equation N2(g) + 3H2(g) ⇌ 2NH3(g). Determine the enthalpy of formation of ammonia
Savatey [412]

Answer:

\Delta _fH_{NH_3}=-66\frac{kJ}{mol}

Explanation:

Hello!

In this case, since the study of the bond energy allows us to compute the enthalpies of some reactions, for this combination reaction by which ammonia is yielded, we understand the enthalpy of reaction equals the enthalpy of formation of ammonia, and, in terms of the bonds energy we can write:

\Delta _fH_{NH_3}=Delta _rH=\Sigma \Delta H(bonds \ broken)-\Sigma \Delta H(bonds \ formed)

Whereas the bonds enthalpy of those bonds that get broken cover the N≡N and the three H-H bonds at the reactants side and the enthalpy of those bonds that are formed cover the six N-H bonds at the products; which means we obtain:

\Delta _fH_{NH_3}=942\frac{kJ}{mol} +3*436\frac{kJ}{mol}-6*386\frac{kJ}{mol}\\\\\Delta _fH_{NH_3}=-66\frac{kJ}{mol}

Which differs from the theoretical value that is -46 kJ/mol.

Best regards!

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The Tin Pan Alley era lasted from 1950 to 1967.<br> a. true<br> b. false
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A 4.00g sample of helium has a volume of 24.4L at a temperature of 25.0 C and a pressure of 1.00 atm. The volume of the helium i
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Answer:

0.852 mol

Explanation:

First we <u>convert 4.00 g of helium (He) into moles</u>, using its <em>molar mass</em>:

4.00 g ÷ 2 g/mol = 2 mol He

To answer this problem we can use<em> Avogadro's law</em>, which states that at constant pressure and temperature:

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We <u>input the data</u>:

  • 24.4 L * n₂ = 10.4 L * 2 mol

And <u>solve for n₂</u>:

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3 years ago
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Neporo4naja [7]

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