All categories

3 years ago

How many hydrogen atoms are in 4.40 mol of ammonium sulfide

2 answers:

katrin2010 [14]3 years ago

5 0

The number of hydrogen atoms that are in 4.40 mol of ammonium sulfide is 2.12 x10^25 atoms

calculation
find the number of moles of Hydrogen in ammonium sulfide (NH4)2S

that is 4.40 x number of hydrogen atoms in (NH4)2S ( 4x2= 8 atoms)

moles is therefore= 4.40 x8= 35.2 moles

by use of Avogadro's law constant

that is 1mole = 6.02 x10^23 atoms
35.2 moles=?

by cross multiplication
{35.2 moles x 6.02 x10^23} /1 mole = 2.12 x10^25 atoms

Ne4ueva [31]3 years ago

4 0

The molecular formula for ammonium sulfide would be (NH4)2S. That means in one molecule of ammonium sulfide there will be 1 N + 4 H + 2 S molecules.
Then the amount of hydrogen atoms in 4.4 moles of ammonium sulfide should be: 4.4 moles * 4/1= 17.6 moles
If you are asked for atom count then the amount should be: 17.6 moles * 6.022x10^23 atoms/mol = 105.9872 * 10^23= 1.06 * 10^25

You might be interested in

Which statements are true of all scientific endeavors? Check all that apply.

dybincka [34]

Scientific endeavors is basically all the things that would contribute to the process of achieving a certain scientific knowledge, from the initial observation, up to the point until we can hold that certain thing as acknowledged truth. So,

All scientific endeavors are supported by evidence.
All scientific endeavors are a systemic process.
All scientific endeavors involve observation.
All scientific endeavors involve experimentation.
All scientific endeavors involve the collection of information.

4 0

3 years ago

Scientists have been able to find a full record of Earth's fossil history, thus making the fossil record complete.

Arada [10]

Answer:

False

Explanation:

Few organisms were not preserved as well as others, and new fossils are found every day

5 0

3 years ago

Convert 321 millimeters to picometers

pantera1 [17]

3.21e+11 is your answer for 321 millimeters in picometers. Hope this helps!

3 0

3 years ago

Suppose of hcl and of o2 are added to an empty flask. How much will be in the flask at equilibrium?A. None. B. Some, but less th

serg [7]

This is an incomplete question, here is a complete question.

Hydrogen chloride and oxygen react to form water and chlorine, like this:

$4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)$

Use this chemical equation to answer the questions in the table below.

Suppose 155. mmol of HCl and 38.8 mmol of O₂ are added to an empty flask. How much HCl will be in the flask at equilibrium?

(1) None.

(2) Some, but less than 155. mmol,

(3) 155. mmol,

(4) More than 155. mmol,

Answer : The correct option is, (1) None

Explanation :

The given balanced chemical reaction is:

$4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)$

From the balanced chemical reaction, we conclude that

As, 4 mmole of HCl react with 1 mmoles of $O_2$

So, 155. mmole of HCl react with $\frac{155.}{4}\times 1=38.75$ mmoles of $O_2$

That means, $O_2$ is excess reagent and $HCl$ is a limiting reagent. All the moles of HCl will consume.

Hence, the correct option is, None.

7 0

3 years ago

A species has the following MO configuration: (σ1s)2(σ1s*)2(σ2s)2(σ2s*)2(σ2p)2(π2p)2. This substance is:_______.

Goshia [24]

Answer : The correct option is, (a) paramagnetic with two unpaired electrons.

Explanation :

According to the molecular orbital theory, the general molecular orbital configuration will be,

$(\sigma_{1s}),(\sigma_{1s}^*),(\sigma_{2s}),(\sigma_{2s}^*),(\sigma_{2p_z}),[(\pi_{2p_x})=(\pi_{2p_y})],[(\pi_{2p_x}^*)=(\pi_{2p_y}^*)],(\sigma_{2p_z}^*)$

As there are 14 electrons present in the given configuration.

The molecular orbital configuration of molecule will be,

$(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^2,(\sigma_{2s}^*)^2,(\sigma_{2p_z})^2,[(\pi_{2p_x})^1=(\pi_{2p_y})^1],[(\pi_{2p_x}^*)^0=(\pi_{2p_y}^*)^0],(\sigma_{2p_z}^*)^0$

The number of unpaired electron in the given configuration is, 2. So, this is paramagnetic. That means, more the number of unpaired electrons, more paramagnetic.

Hence, the correct option is, (a) paramagnetic with two unpaired electrons.

3 0

3 years ago