Question

Calcium Carbonate decomposes at 1200°C to form carbon dioxide and

Answer 1

This is a Charles' Law problem: V1/T1 = V2/T2. As the temperature of a fixed mass of gas decreases at a constant pressure, the volume of the gas should also decrease proportionally.

To use Charles' Law, the temperature must be in Kelvin (x °C = x + 273.15 K). We want to solve Charles' Law for V2, which we can obtain by rearranging the equation into V2 = V1T2/T1. Given V1 = 25 L, T1 = 1200 °C (1473.15 K), and T2 = 25 °C (298.15 K):

V2 = (25 L)(298.15 K)/(1473.15 K) = 5.1 L.