As the [H] In a solution decreases, what happens to the [OH-]?

What is the molarity of a HCl solution, if 28.6 mL of a 0.175 m NaOH solution is needed to neutralize a 25.0 mL sample of the HC

Katen [24]

The molarity of the HCl solution needed to neutralize 28.6 mL of a 0.175 M NaOH solution is 0.2002 M

We'll begin by writing the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 1

The mole ratio of the base, NaOH (nB) = 1

From the question given above, the following data were obtained:

Volume of base, NaOH (Vb) = 28.6 mL

Molarity of base, NaOH (Mb) = 0.175 M

Volume of acid, HCl (Va) = 25 mL

<h3>Molarity of acid, HCl (Ma) = ?</h3>

The molarity of the acid, HCl can be obtained as follow:

MaVa / MbVb = nA / nB

(Ma × 25) / (0.175 × 28.6) = 1

(Ma × 25) / 5.005 = 1

Cross multiply

Ma × 25 = 5.005

Divide both side by 25

Ma = 5.005 / 25

Therefore, the molarity of the acid, HCl needed for the reaction is 0.2002 M

Learn more: brainly.com/question/25573711

7 0

3 years ago

An elixir of ferrous sulfate contains 220 mg of ferrous sulfate in each 5 ml. if each milligram of ferrous sulfate contains the

natita [175]

To determine the mass of elemental iron in the elixir, we need to understand the given values given above. We are given the following:

Mass of ferrous sulfate = 220 mg
Volume of the elixir = 5 mL
Mass of elemental iron / mass of ferrous sulfate = 0.2 mg Fe / mg ferrous sulfate

Therefore, from the given values, we simply multiply the mass of the ferrous sulfate in the elixir and the equivalent mass of elemental iron per mass of ferrous sulfate. We do as follows:

Mass of Fe = 220 mg ferrous sulfate ( 0.2 mg Fe / mg ferrous sulfate )
Mass of Fe = 44 mg

7 0

4 years ago

In the laboratory you dilute 2.49 ml of a concentrated 6.00 m hydrochloric acid solution to a total volume of 50.0 ml. what is t

Marizza181 [45]

Equation: M1V1 = M2V2

Where M = concentration & V = volume

Step 1: Write down what is given and what you are trying to find

Given: M1 = 6.00M, V1 = 2.49mL, and V2 = 50.0mL
Find: M2

Step 2: Plug in the values into the equation

M1V1 = M2V2
(6.00M)(2.49mL) = (M2)(50.0mL)

Step 3: Isolate the variable (Divide both sides by 50.0mL so M2 is by itself)

(6.00M)(2.49mL) / (50.0mL) = M2

Answer: M2 = 0.30M
*Don't forget sig figs & units!

4 0

3 years ago

If you have 100 particles of hydrogen and 100 particles of oxygen, how many units of water can you form? Will you use all the pa

m_a_m_a [10]

Answer:

82

Explanation:

i took the assingment

3 0

3 years ago

How many moles of chloride ions are there in 2 moles of calcium chloride?

Oksana_A [137]

Answer:

<em>There are </em><u><em>4 moles</em></u><em> of chloride ions in 2 moles of calcium chloride.</em>

Explanation:

Start by writing the chemical formula of calcium chloride.

The suffix -ide in chloride means that chlorine is working as the ion Cl⁻, this is with oxidation state -1.

Calcium, being an alkaline earth metal, uses oxidation state +2, Ca²⁺

Then, two atoms of Cl are combined with one atom of calcium, because in this way each Cl atom will accept one electron from a Ca atom, which will donate its two valence electrons.

That is indicated in the chemical formula with subscripts: <u><em>CaCl₂</em></u>, meaning that each formula-unit of calcium chloride has 2 ions of chlorine and 1 ions of calcium, or twice the number of moles of chloride ion.

1 mol CaCl₂ : 1 mol Ca⁺ : 2 mol Cl⁻

⇒ 2 mol CaCl₂ : 2 mol Ca⁺ : 4 mol Cl⁻

Hence, there are 4 moles of chloride ions in 2 moles of calcium chloride.

6 0

3 years ago