Answer : A - carboxyl group.
The carbon in the carboxyl group is bonded to a hydroxyl group and also it is double bonded to an oxygen group.
The carboxyl group when it is dissolved in a solution donates it's hydrogen ion(H+ ion). When it is dissolved in water, the carboxyl group loses its H+ ion to form negatively charged ion.
RCOOH + H2O⇄RCOO- + H3O+
Thus the carboxyl group act as an acid when dissolved in water.
Answer:
K = 8x10¹⁸
Explanation:
<em>When you sum a reaction, the result of this sum has a K equal to the multiplication of the K's of the reactions involved in the sum</em>
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The sum of two times the reaction:
NaO(g) ⇌ Na(l) + 1/2 O₂(g) K₂ = 2x10⁻⁵
2 NaO(g) ⇌ 2 Na(l) + O₂(g) K = K₂ₓK₂ = (2x10⁻⁵)² = 4x10⁻¹⁰
The result of the inverse reaction:
Na₂O₂(s) ⇌ 2 Na(l) + O₂(g) K₃= 5x10⁻²⁹
2 Na(l) + O₂(g) ⇌ Na₂O₂(s) K = 1/K₃ = 2x10²⁸
And the sum of the two bolded reactions:
2 NaO(g) + 2 Na(l) + O₂(g) ⇌ 2 Na(l) + O₂(g) + Na₂O₂(s)
2 NaO(g) ⇌ Na₂O₂(s) K = 4x10⁻¹⁰× 2x10²⁸
<h3>K = 8x10¹⁸</h3>
Genetic diversity :
1. It is related to number of genes and their alleles found in organisms.
2. It is trait of the species.
3. It influences adaptability and distribution of a species in diverse habitats.
Example :
Humans have created distinct breeds of dogs within the species by selectively breeding individuals with traits that they want. The genetic variability within these breeds is decreased because their effective population size is limited by humans controlling their access to mates.
Species Diversity:
1. It is related to number and distribution of species found in an area.
2. It is trait of the community.
3. It influences biotic interactions and stability of the community.
Example :
the presence of four or five different species of tree in a woodland forest, or perhaps 100 different species of fish, crustaceans and coral in a certain reef.
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Here is the answer
http://m.imgur.com/tJ2WwiN
Answer is: 0,0095 mol of hydrogen gas will be produced in reaction.
Chemical reaction: Ca + 2HCl → CaCl₂ + H₂.
m(Ca) = 0,38 g.
n(H₂) = ?
n(Ca) = m(Ca) ÷ M(Ca).
n(Ca) = 0,38 g ÷ 40 g/mol
n(Ca) = 0,0095 mol.
from reaction: n(Ca) : n(H₂) = 1 : 1.
n(H₂) = n(Ca) = 0,0095 mol.
n - amount of substance.