Answer: It would be A and C
Explanation: I did the test and got it right. Hope this helps!
The symbol of the radioactive nuclide, given the data is ⁴⁰₁₉K
<h3>Data obtained from the question</h3>
- Atomic number = 19
- Mass number = 40
- Symbol of nuclide =?
<h3>How to determine the nuclide</h3>
From the question given above, the atomic number of the nuclide is 19.
Comparing the atomic number (i.e 19) of the nuclide with those in the periodic table, the nuclide is potassium with a symbol of K
<h3>How to determine the symbol of the nuclide</h3>
- Atomic number (Z) = 19
- Mass number (A) = 40
- Name of nuclide = Potassium (K)
- Symbol of nuclide =?
The symbol of a nuclide is given as ᴬ₂X
Where
- A is the mass number
- Z is the atomic number
- X is the symbol of the element
Thus,
ᴬ₂X => ⁴⁰₁₉K
Therefore, the symbol of the nuclide is ⁴⁰₁₉K
Learn more about composition of atoms:
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Answer:
F. 2NO + 02 —> 2NO
H. 4NH3 + 502 —> 4NO + 6H20
Explanation:
The law of conservation of mass states that matter can neither be created nor destroyed during a chemical reaction but can be convert from one form to another.
2NO + 02 —> 2NO
From the above, the total number of N on the left balance the total number on the right i.e 2 atoms of N on both side of the equation.
The total number of O on the left balance the total number on the right i.e 2 atoms of O on both side of the equation. This is certified by the law of conservation of mass.
4NH3 + 502 —> 4NO + 6H20
From the above, the total number of N on the left balance the total number on the right i.e 4 atoms of N on both side of the equation.
The total number of O on the left balance the total number on the right i.e 10 atoms of O on both side of the equation.
The total number of H on the left balance the total number on the right i.e 12 atoms of O on both side of the equation.
This is certified by the law of conservation of mass.
The rest equation did not conform to the law of conservation of mass as the atoms on the left side did not balance those on the right side
Answer:
5.6L
Explanation:
At STP, the pressure and temperature of an ideal gas is
P = 1 atm
T = 273.15k
Volume =?
Mass = 9.5g
From ideal gas equation,
PV = nRT
P = pressure
V = volume
n = number of moles
R = ideal gas constant =0.082J/mol.K
T = temperature of the ideal gas
Number of moles = mass / molar mass
Molar mass of F2 = 37.99g/mol
Number of moles = mass / molar mass
Number of moles = 9.5 / 37.99
Number of moles = 0.25moles
PV = nRT
V = nRT/ P
V = (0.25 × 0.082 × 273.15) / 1
V = 5.599L = 5.6L
The volume of the gas is 5.6L
