Which of the protist is the most complex organism ?
A) paramecium
<u>B) amoeba
</u>
C) Euglena
D) Volvox
Answer:
Sample A - mixture
Sample B- Mixture
Explanation:
Looking at sample A, we can see that as water was poured over sample A, the sample was separated into its components as the powder disappeared leaving behind a gritty black sand-like material on the surface of the paper. A separation of the mixture has taken place.
In sample B, we can clearly see that it is a mixture because the amount of solid recovered is much less than the total mass of the solid put into the beaker. The sample must have been separated into its components.
Answer:
(a) SeF₄
(b) OF₂
(c) N₂O
(d) PCl₃
Explanation:
Write the formula for each compound.
(a) selenium tetrafluoride. According to the name, this compound has 1 atom of Se and 4 atoms of F. The resulting formula is SeF₄, in which Se has the oxidation number 4+ and F has the oxidation number 1-.
(b) oxygen difluoride. According to the name, this compound has 1 atom of O and 2 atoms of F. The resulting formula is OF₂, in which the oxidation number of O is 2+ and the oxidation number of F is 1-.
(c) dinitrogen monoxide. According to the name, this compound has 2 atoms of N and 1 atom of O. The resulting formula is N₂O, in which the oxidation number of N is 1+ and the oxidation number of O is 2-.
(d) phosphorus trichloride. According to the name, this compound has 1 atom of P and 3 atoms of Cl. The resulting formula is PCl₃, in which the oxidation number of P is 3+ and the oxidation number of Cl is 1-.
The answer is malleability.
Explanation:
a) Using Beer-Lambert's law :
Formula used :
where,
A = absorbance of solution = 0.22
C = concentration of solution = 
l = length of the cell = 3.0 cm
= molar absorptivity of this solution = ?
Now put all the given values in the above formula, we get the molar absorptivity of this solution.
Therefore, the molar absorptivity of this solution is, 
b) 
A = 2 × 0.22 =0.44
= Intensities of Incident light and transmitted light respectively
T = Transmittance
T = 0.3630
c) 
Thickness of cell = l' =?
l' = 1.53 cm
d) No, we cannot calculate the absorbance at 590 nm from the given data. This is because absorbance at this wavelength can be observe experimentally.
