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2 years ago

List the sides of the triangle in order from shortest to longest

Mathematics

1 answer:

-BARSIC- [3]2 years ago

5 0

Answer:

To put the sides in order of longest to shortest, first find the largest angle -- the longest side is opposite this angle. Then, find the second largest angle and the side opposite from it to find the next largest angle, and finally, the shortest side will be opposite the smallest angle.

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I really need help with my homework. <br><br> factorise 10x+25

alina1380 [7]

5(2x + 5), because 10x and 25 only have 5 in common, which is why it's outside the bracket, and 5 × 2x is 10x, and 5 × 5 is 25. Hope this helps!

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2 years ago

Read 2 more answers

I need help with like terms

professor190 [17]

I’m guessing you mean like this.
2x+4y+5x+8y.
2x and 5x are like terms because the x’s are alike. If you add 2+5, the answer is 7. So therefore 2x+5x=7x.

4y and 8y are like terms because the y’s are alike. So the answer to 4y+8y would be 12y.

If you need extra help, give me a problem and I will help you solve it.

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2 years ago

Find the measure of the missing angle.<br> 21°<br> a

Citrus2011 [14]

Answer:

write complete question...

so,I can solve it

Step-by-step explanation:

mark me brainliest

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2 years ago

There are 1,200 students at roosevelt middle school. There are 700 boys at the school. What percentage of the students at roosev

Marat540 [252]

Answer:

100x=256.25

Step-by-step explanation:

x/1025=25/100

What is 25% of 1025

that would be 1025×25

100x=256.25

3 0

2 years ago

(a) Let {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it app

Nataliya [291]

Answer:

0.625

Step-by-step explanation:

Given that {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it applies to the partition {A1, A2} and the event B.

Since A1 and A2 are mutually exclusive and exhaustive, we can say

b) P(B) = P(A1B)+P(A2B)

Selecting any one coin is having probability 0.50. and A1, A2 are events that the coins show heads. $P(B/A1) = 0.50 \\P(B/A2) = 0.75\\P(A1B) = 0.5(0.5) = 0.25 \\P(A2B) = 0.75(0.5) = 0.375\\P(B) = 0.625$

c) Using Bayes theorem

conditional probability that it wasthe biased coin

= $\frac{0.375}{0.625} \\=\frac{3}{5}$

d) Given that the chosen coin flips tails,the conditional probability that it was the biased coin= $\frac{0.25*0.5}{0.25*0.5+0.5*0.5} \\=\frac{1}{3}$

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2 years ago