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3 years ago

The diameter of a circle is 2 meters. What is the area? Exact answer in simplest form

Mathematics

2 answers:

kow [346]3 years ago

7 0

Answer:

22/7

Step-by-step explanation:

Diameter is 2m

we know,

radius= Diameter/2

r = d/2

r = 2/2

r = 1

Now,

area of circle= πr^2

22/7 * 1^2

22/7 ....... answer

loris [4]3 years ago

7 0

Answer:

r=d/2

r=2/2

r=1

area=22/7×r

22/7×1

=31/7

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4x + 4y = -8<br> -22 – 2y = 4

Natalka [10]

Answer:

1) 4x + 4y = -8

x=-2-y

y=-2-x

2) 22 – 2y = 4

y=9

Step-by-step explanation:

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2 years ago

If one-half of a number decreased by 20 is 40, what is the number?

Anvisha [2.4K]

Answer:

120

Step-by-step explanation:

Just add the 20 back to 40 and times by 2

40 + 20 = 60

60 * 2 = 120

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2 years ago

Read 2 more answers

Credit sales are collected as follows:65 percent in the month of the sale.25 percent in the month after the sale.10 percent in t

Vitek1552 [10]

Answer:

Step-by-step explanation:

a) November sales = (Total Uncollected Sales - Uncollected Sales from December) / Collection rate after two months

= ($121,100 - $87,300) / 0.20

November sales = $169, 000.00

b) December sales = Uncollected sales from December / Collection rate of the previous month sales,

Therefore: December sales = $87,300 / 0.45 = $194,000

December sales = $194,000.00

c) Each month's collection for the company are:

Collections for ech month = 0.20(Sales from 2 months ago) + 0.25(Last month's sales) + 0.55 (Current sales)

January collections = 0.20($169000.00) + 0.25($194,000.00) + 0.55($132,000)

January collections = $154,900.00

February collections = 0.20($194,000.00) + 0.25($132,000) + 0.55($149,000)

February collections = $153,750.00

March collections = 0.20($132,000) + 0.25($149,000) + 0.55($164,000)

March collections = $153,850.00

4 0

3 years ago

The square root of 9x^4/36 simplified

Serggg [28]

Step-by-step explanation:

$\sqrt{ \frac{9 {x}^{4} }{36} } \\ \\ = \sqrt{ \frac{ {x}^{4} }{4} } \\ \\ = \frac{ {x}^{2} }{2}$

6 0

3 years ago

What multiplies to -12 but added together equals -10

Airida [17]

Let the two numbers be x and y, then,
xy = -12 . . . (1)
x + y = -10 . . . (2)
From (2), x = -10 - y . . . (3)
Putting (3) into (1), gives
(-10 - y)y = -12
-10y - y^2 = -12
y^2 + 10y - 12 = 0
$y= \frac{-10\pm \sqrt{10^2-(4\times(-12))} }{2} = \frac{-10\pm \sqrt{148} }{2} = \frac{-10\pm 2\sqrt{37} }{2} = -5\pm\sqrt{37}$

Therefore, the two numbers are $-5+\sqrt{37}$ and $-5-\sqrt{37}$

4 0

3 years ago