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kondaur [170]
4 years ago
5

if 1 centimeter on the scale drawing represents 3 feet what will be the diameter of clarise's fish pond

Mathematics
2 answers:
Amanda [17]4 years ago
7 0
Well how many centimeters
defon4 years ago
6 0
Is there a picture to go with it?

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To adopt a dog from an animal shelter, you must pay $80 for vaccinations, $65 to spay or neuter the dog, and $50 for a wellness
Leya [2.2K]

The equation with (x) in dogs and (y) in dollars is  y=195x

First, you must set up your equation.

y=80x+65x+50x

Then, you must add like terms to simplify the equation

y=195x

4 0
3 years ago
The graph of the function f(x) =ax2+bc+c is given below. Could the factors of f(x) be (x+2) and (x+4)? Based on the graph, expla
Alchen [17]

Answer:

 neither can be a factor

Step-by-step explanation:

If (x -a) is a factor, then value of the function will be zero at x=a. Here, the function has a value of zero (x-intercept) at x = -1 and x = 3. Hence (x+1) and (x-3) are factors, but (x+2) and (x+4) are not. The function is non-zero at x=-2 and x=-4.

5 0
3 years ago
To the nearest tenth, what is the distance between the points (1, –2, 5) and (0, 7, –4)?
Eduardwww [97]

Answer:

The distance is 12.8\ units

Step-by-step explanation:

we know that

The formula to calculate the distance between two points is equal to

d=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}+(z2-z1)^{2}}

we have

A(1,-2,5)\\B(0,7,-4)  

substitute the values

d=\sqrt{(0-1)^{2}+(7+2)^{2}+(-4-5)^{2}}

d=\sqrt{(-1)^{2}+(9)^{2}+(-9)^{2}}

d=\sqrt{1+81+81}

d=\sqrt{163}\ units

d=12.8\ units

8 0
3 years ago
There are 60 members in the school glee club.the glee club needs to raise at least $5,000 for a trip to a national competition.t
Vikentia [17]
4,000 more dollars. Because if each class needs 5,00 then 1,000 + 4,000 equals 5,000. 60*something is 5,000.
7 0
3 years ago
Find the perimeter of △ABC with vertices A(−5, −5), B(3, −5), and C(−5, 1).
icang [17]
Check the picture below.

so notice, the sides AB and AC you can pretty much count them off the grid.

now, to get the CB side.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
C&({{ -5}}\quad ,&{{ 1}})\quad 
%  (c,d)
B&({{ 3}}\quad ,&{{ -5}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
CB=\sqrt{[3-(-5)]^2+[-5-1]^2}\implies CB=\sqrt{(3+5)^2+(-5-1)^2}
\\\\\\
CB=\sqrt{8^2+(-6)^2}\implies CB=\sqrt{100}\implies CB=10

sum all three sides up, and that's the perimeter of the triangle.

4 0
3 years ago
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