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3 years ago

Friends anyone ?17 and up

Chemistry

1 answer:

LenaWriter [7]3 years ago

6 0

Answer:

im14 wth

Explanation:

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What did Aristotle believe?

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Answer:

He believed in biology

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4 years ago

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Bile salt from the gall bladder mix with fats to further break them down in a process called emulsification

Explanation

Emulsification involve breakdown of large fat globules into tiny droplet in the duodenum. This provide a large surface area on which the enzyme pancreatic lipase can act to digest the fats into fatty and qlycerol. Emulsification is assisted by action of bile salt where the secreted bile in the liver and stored in the gallbladder is released to the duodenum .

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4 years ago

How many liters of

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The balanced equation for the above reaction is as follows
C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂<span>(g)
the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction.
the amount of </span>C₆H₁₂O₆ used up - 13.2 g
the number of moles reacted - 13.2 g/ 180 g/mol = 0.073 mol
stoichiometry of glucose to CO₂ - 1:6
then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol
As mentioned this reaction takes place at standard temperature and pressure conditions,
At STP 1 mol of any gas occupies 22.4 L
Therefore 0.44 mol of CO₂ occupies 22.4 L/mol x 0.44 mol = 9.8 rounded off - 10.0 L
Answer is B) 10.0 L CO₂

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4 years ago

Calculate the standard entropy change for the following reaction cu(s) + 1/2 O2(g) —> cuo(s)

Evgen [1.6K]

3433Explanation:

the awser sucks and its not RIGHT

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3 years ago

Read 2 more answers

How many grams of kclo3 are needed to make 30.0 grams of kcl

lubasha [3.4K]

The mass of potassium chlorate, KClO₃ needed to produce 30 grams of potassium chloride, KCl is 49.33 grams

<h3>Balanced equation </h3>

2KClO₃ —> 2KCl + 3O₂

Molar mass of KClO₃ = 39 + 35.5 + (16×3) = 122.5 g/mol

Mass of KClO₃ from the balanced equation = 2 × 122.5 = 245 g

Molar mass of Kcl= 39 + 35.5 = 74.5 g/mol

Mass of KCl from the balanced equation = 2 × 74.5 = 149 g

SUMMARY

From the balanced equation above,

149 g of KCl were obtained from 245 g of KClO₃

<h3>How to determine the mass of KClO₃ needed </h3>

From the balanced equation above,

149 g of KCl were obtained from 245 g of KClO₃

Therefore,

30 g of KCl will be obtained from = (30 × 245) / 149 = 49.33 g of KClO₃

Thus, 49.33 g of KClO₃ are needed for the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

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2 years ago