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Rom4ik [11]
2 years ago
8

Tryptophan is one of the amino acids found in proteins:

Chemistry
1 answer:
evablogger [386]2 years ago
4 0

Tryptophan is one of the amino acids found in protein and it has 28 sigma bonds present in the tryptophan.

<h3>What is  tryptophan?</h3>

Tryptophan is an essential amino acid that serves several important purposes, like nitrogen balance in adults and growth in infants. Tryptophan is an amino acid needed for normal growth in infants and for the production and maintenance of the body's proteins, muscles, enzymes, and neurotransmitters. It is an essential amino acid that  means your body cannot produce it. The body uses tryptophan to help make melatonin and serotonin. Melatonin helps regulate the sleep-wake cycle, and serotonin is thought to help regulate appetite, sleep, mood, and pain.

To learn more about tryptophan, visit;

https://brainly.in/question/1158606

#SPJ4

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Calculate the freezing point of the solution containing 0.105 m k2s. calculate the boiling point of the solution above. -g
Licemer1 [7]
Quantity of K2S m = 0.105 m 
Number of ions i = 2(K) + 1(S) = 3
 Freezing point depression constant of water Kf = 1.86 
delta T = i x m x Kf = 3 x 0.105 x 1.86 = 0.586
 Freezing point = 0 - 0.586 = 0.586 C
 Boiling point constant of water Kb = 0.512
 delta T = i x m x Kb = 3 x 0.105 x 0.512 = 0.161
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Lauryl alcohol is a nonelectrolyte obtained from coconut oil and is used to make detergents. A solution of 6.80 g of lauryl alco
natka813 [3]

Answer:

The approximate molar mass of lauryl alcohol is 174.08 g/m

Explanation:

An excersise to apply the colligative property of Freezing-point depression.

This is the formula: ΔT = Kf . m

First of all, think the T° of fusion of benzene → 5.5°C

ΔT = T° pure solvent - T° fusion solution

Kf for benzene: 5.12 °C/m

5.5°C - 4.5°C = 5.12 °C /m  . m

1°C /  5.12 m /°C = m

0.195 m = molality

This moles of lauryl alcohol, solute, are in 1 kg of benzene, solvent.

I have to find out in 0.2 kg.

1 kg sv ____ 0.195 moles solute

0.2 kg sv ____ (0.195 . 0.2)/1 = 0.039 moles solute

The mass for these moles is 6.80 g, so if I want to know the molar mass, I have to divide mass / moles

6.80 g/ 0.039 moles = 174.08 g/m

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3 years ago
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