Answer:
C1V1=C2V2
C1 is 2.0mol/l
V1=?
C2=.4mol/L
V2=100ml or for this 0.1L
V1 is 20ml
Best way to prepare this is to measure out 20ml of the 2 molar solution and add 80mL to it to get to 100mL
Explanation:
Answer:
There is 5.56 g of gold for every 1 g of chlorine
Explanation:
The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction 
You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

The proportion is the equal relationship that exists between two reasons and is represented by: 
This reads a is a b as c is a d.
To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

Solving for the mass of gold gives:

mass of gold= 5.56 grams
So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>
Average speed in km/h:
S = D/T
T = 10/60 hrs
= 0.1667
S = 10 / 0.1667
= 59.988 km/h
The one on top is corrrect because the cell diagram will always contain one object or more