We can let x be the number of boxes sold for the first week. We can as well express the number of boxes for the second and third week through x using the statements provided.

Since the girl scout sold 5 more boxes on the second week, we have (x + 5) number of boxes sold for the second week. Now, for the third week, since it's double that of the second week, we have 2(x + 5). Thus, we have the following:

first week: x
second week: x + 5
third week: 2(x + 5)

Given that the total number of boxes sold for the three weeks is 431. We have

x + (x + 5) + 2(x + 5) = 431
x + x + 5 + 2x + 10 = 431
4x + 15 = 431
4x = 431 - 15
4x = 416
x = 104

We have now the value of x. Using this, we can find the values for the second and third week.
x + 5 = `104 + 5 = 109
2(x + 5) = 2(109) = 218

Answer:
first week: 104
second week: 109
third week: 218

5 0

3 years ago

F(x)= (x-1)(x(x+1)+2x) find all rational zeros

pantera1 [17]

Answer:

x = 0, x = 1, x = - 3

Step-by-step explanation:

To find the zeros, let f(x) = 0 , that is

(x - 1)(x(x + 1) + 2x) = 0 ← distribute and simplify parenthesis

(x - 1)(x² + x + 2x) = 0

(x - 1)(x² + 3x) = 0 ← factor out x from the second parenthesis

x(x - 1)(x + 3) = 0

Equate each factor to zero and solve for x

x = 0

x - 1 = 0 ⇒ x = 1

x + 3 = 0 ⇒ x = - 3

5 0

3 years ago