With what? what’s the question
Given :
A line 2x + 1 =0 .
To Find :
The slope of the given line .
Solution :
We know , slope of line is given by the tangent of the angle between the x-axis and the line .
Now, for line 2x + 1 =0 i.e
.
The line is perpendicular to x-axis and cuts the x-axis at
.
Therefore , the angle between the line and x-axis is
.
So , slope
i.e undefined .
Therefore , the slope of given line is not defined .
Hence , this is the required solution .
Check the picture below.
since we know that x = 3/7, we can then plug that on either of the twin legs, since it's an isosceles, and get the length of each leg, so say let's plug it in 5x + 16
![5x + 16\implies 5\left( \cfrac{3}{7} \right)+16\implies \cfrac{38}{7}+16\implies \cfrac{38+112}{7}\implies \cfrac{150}{7}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\\stackrel{\textit{both legs}}{\cfrac{150}{7}+\cfrac{150}{7}}+\stackrel{\textit{base}}{6}\implies \cfrac{150+150+42}{7}\implies \cfrac{342}{7}\implies 48\frac{6}{7}\impliedby \textit{perimeter}](https://tex.z-dn.net/?f=5x%20%2B%2016%5Cimplies%205%5Cleft%28%20%5Ccfrac%7B3%7D%7B7%7D%20%5Cright%29%2B16%5Cimplies%20%5Ccfrac%7B38%7D%7B7%7D%2B16%5Cimplies%20%5Ccfrac%7B38%2B112%7D%7B7%7D%5Cimplies%20%5Ccfrac%7B150%7D%7B7%7D%5C%5C%5C%5C%5B-0.35em%5D%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%5Cstackrel%7B%5Ctextit%7Bboth%20legs%7D%7D%7B%5Ccfrac%7B150%7D%7B7%7D%2B%5Ccfrac%7B150%7D%7B7%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bbase%7D%7D%7B6%7D%5Cimplies%20%5Ccfrac%7B150%2B150%2B42%7D%7B7%7D%5Cimplies%20%5Ccfrac%7B342%7D%7B7%7D%5Cimplies%2048%5Cfrac%7B6%7D%7B7%7D%5Cimpliedby%20%5Ctextit%7Bperimeter%7D)
What are you trying to do with this?