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Vlad1618 [11]
3 years ago
6

Four doughnuts and 4 coffees cost $12. The cost of the 4 coffees is half the cost of the 4 doughnuts. What is the cost of each c

offee? Which of the following problems would help you solve the problem above? A. What is the cost of each doughnut? B. What is the cost of the 4 coffees together? C. What is the cost of 8 doughnuts and 8 coffees? D. What is the cost of 2 doughnuts and 2 coffees?
Mathematics
1 answer:
Tems11 [23]3 years ago
5 0
I think A is the answer you are looking for

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A population of 60 foxes in a wildfire preserve doubles in size every 12 years. The function y = 60*2^x, where x is the number o
alexira [117]
There will be 240 foxes
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3 years ago
Which athletes, if any, would qualify for the finals if the length of a jump that qualifies for the finals were at least 20 feet
saul85 [17]

Answer:

Amir and ryan would qualifiey

Step-by-step explanation:

5 0
2 years ago
(50 points and brainliest.Need help ASAP)
Aleksandr-060686 [28]

Answer:  " 2x (2x - 1) (x + 1) " .

______________________________________

Step-by-step explanation:

______________________________________

Given:  

  f(x)   =  9x³ + 2x² − 5x  + 4  ;

  g(x)  =  5x³ − 7x + 4 ;

______________________________________

What is:  f(x) − g(x) ?

______________________________________

Plug in:  " 9x³ + 2x² − 5x + 4 "  for:  " f(x) " ;

    and:   " (5x³ − 7x + 4) " ;  for:  "g(x)" ;

______________________________________

→  " f(x) − g(x)   =  

   

       " 9x³ + 2x² − 5x + 4  − (5x³ − 7x + 4) "  .

______________________________________

Rewrite this expression as:

 →  " 9x³ + 2x² − 5x + 4  − 1(5x³ − 7x + 4) "  .

 →   {since:  " 1 " ;  multiplied by "any value" ;  is equal to that same value.}.

______________________________________

Now, let us example the following portion of the expression:

______________________________________

 "  − 1(5x³ − 7x + 4) "

_____________________________________

Note the "distributive property"  of multiplication:

______________________________________

    →   a(b + c) = ab + ac ;

______________________________________

Likewise:

     →  a(b + c + d) = ab + ac + ad .

______________________________________

As such:

______________________________________

    →  "  − 1(5x³ − 7x + 4)  "  ;

______________________________________

             =   (-1 * 5x³) + (-1 * 7x) + (-1 * 4) ;

             =  - 5x³  +  (-7x)  +  (-4)  ;

             =   - 5x³  − 7x − 4  ;

_____________________________________

Now, add the "beginning portion of the expression" ; that is:

  " f(x) " ;  to the expression ;  which is:

                        →   9x³ + 2x² − 5x  +  4  ;

 →  as follows:  

_______________________________________

 →  9x³ + 2x² − 5x  +  4 − 5x³ − 7x − 4  ;

 →  {Note that the:  " - " sign; that is;

       the "negative sign", in the term:  " -5x³ " ;

       becomes a: " − " sign; that is; a "minus sign" .}.

______________________________________

Now, combine the "like terms" of this expression; as follows:

  + 9x³  −  5x³  =  + 4x³ ;

 − 5x − 7x  =  − 2x ;

 + 4 − 4 = 0 ;

______________________________________

and we have:

______________________________________

 →     " 4x³  +  2x²  − 2x ".

______________________________________

Now, to write this answer in "factored form" :

Note that among all 3 (three) terms in this expression, each term has a factor of "2" .  The lowest coefficient among these 3 (three) terms is "2" ;  so we can "factor out" a "2".  

Also, each of the 3 (three) terms in this fraction is a coefficient to a variable.  That variable takes the form of "x".  The term in this expression  with the variable, "x";  with the lowest degree has the variable: "x" (i.e. "x¹ = x" ) ;  so we can "factor out a "2x" (rather than just the number, "2".).

So, by factoring out a "2x" ;  take the first term [among the 3 (three) terms in the expression] —which is:  "4x³ " .

2x * (?)  = 4x³  ?  ;'

↔  \frac{4x^3}{2x} = ? ;

→  4/2 = 2 ;

\frac{x^{3}}{x} = \frac{x^3}{x^1}  = x^{(3-1)} =  x^{2} ;  

As such:   2x * (2x²)  =  4x³ ;

___________________________________________

Now, by factoring out a "2x" ;  take the second term [among the 3 (three) terms in the expression] — which is:  "2x² " .

2x * (?) = 2x²  ? ;

↔   \frac{2x^{2}}{2x} =  ?

→  2/2 = 1 ;

→  \frac{x^{2}}{x} = \frac{x^2}{x^1}= x^{(2-1)} } = x^1 = x ;

As such:  2x * (x) = 2x²

__________________________________________

Now, by factoring out a "2x" ;  take the third term [among the 3 (three) terms in the expression] — which is:  " − 2x " .

2x * (?) =  - 2x ;

↔  \frac{-2x}{2x} = -1 ;

As such:  2x * (-1) =  − 2x .  

__________________________________________

So:

__________________________________________

Given the simplified expression:

 →     " 4x³  +  2x²  − 2x " ;

We can "factor out' a:  " 2x " ;  and write the this answer is: "factored form" ; as:

__________________________________________

  "2x (2x²  +  x  −  1 ) . "

Now, we can further factor the:

    " (2x²  +  x  −  1) " ; portion;

Note:  "(2x² + x - 1)" =

2x² + 2x - 1x -1 = (2x -1) + x (2x - 1 ) =

(2x - 1)  ( x + 1)

_______________________________________

Now, bring down the "2x" ; and write the Full "factored form" ; as follows:

_______________________________________

    →   " 2x (2x - 1) (x + 1) "  .

_______________________________________

Hope this helps!

 Wishing you the best!

_______________________________________

7 0
3 years ago
Use appropriate algebra and theorem 7.2.1 to find the given inverse laplace transform. (write your answer as a function of t.) ℒ
castortr0y [4]

We assume you want to find the inverse transform of s/(s^2 +3s -4). This can be written in partial fraction form as

(4/5)/(s+4) + (1/5)/(s-1)

which can be found in a table of transforms to be the transform of

(4/5)e^(-4t) + (1/5)e^t


_____

There are a number of ways to determine the partial fractions. They all start with factoring the denominator.

s^2 +3x -4 = (s+4)(s-1)


After that, you can postulate the final form and determine the values of the coefficients that make it so. For example:

A/(s+4) + B/(s-1) = ((A+B)s + (4B-A))/(s^2 +3x -4)


This gives rise to two equations:

(A+B) = 1

(4B-A) = 0

4 0
3 years ago
Consider that the length of rectangle A is 10 cm and its width is 6 cm. Which rectangle is similar to rectangle A? A) A rectangl
HACTEHA [7]
ANSWER

B) A rectangle with a length of 15 cm and a width of 9 cm.

EXPLANATION

The given rectangle, A, has length, 10cm and its width is 6cm.

The rectangle that is similar to rectangle A, has the corresponding sides in the same proportion.

For option A, the triangle has length 9cm and width 6cm.

The ratio of the corresponding sides are:

\frac{10}{9} \ne \frac{6}{6}

Since the ratios are not equal, the two triangles are not similar.

For the triangle in option B, the length is 15cm and the width is 9cm.

The ratio of the corresponding sides are:

\frac{10}{15} = \frac{6}{9} = \frac{2}{3}

Since the sides of the triangle are in the same proportion, the two triangles are similar.

For option C, the proportions are not the same.

\frac{10}{14} \ne \frac{6}{7}

The proportions are not the same for the triangle in option D.

\frac{10}{12} \ne \frac{6}{8}
8 0
3 years ago
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