We can use the equation
to find the length of the side of a square.
<u>Solution:</u>
Given that, the perimeter of a square is equal to the perimeter of an equilateral triangle.
The length of a side of the square is given by "x"
And the length of a side of the equilateral triangle is given by "y"
Finding the equation to determine value of "x"
<em><u>The perimeter of a square with side "x" is given as:</u></em>
![\text { perimeter of a square }=4 \times \text { side }=4 x](https://tex.z-dn.net/?f=%5Ctext%20%7B%20perimeter%20of%20a%20square%20%7D%3D4%20%5Ctimes%20%5Ctext%20%7B%20side%20%7D%3D4%20x)
<em><u>Perimeter of a equilateral triangle with side "y" is given as:</u></em>
![\text { perimeter of a equilateral triangle }=3 \text { side }=3 y](https://tex.z-dn.net/?f=%5Ctext%20%7B%20perimeter%20of%20a%20equilateral%20triangle%20%7D%3D3%20%5Ctext%20%7B%20side%20%7D%3D3%20y)
Given that perimeter of a square = perimeter of an equilateral triangle
![\begin{array}{l}{\rightarrow 4 x=3 y} \\\\ {\rightarrow x=\frac{3}{4} y}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Crightarrow%204%20x%3D3%20y%7D%20%5C%5C%5C%5C%20%7B%5Crightarrow%20x%3D%5Cfrac%7B3%7D%7B4%7D%20y%7D%5Cend%7Barray%7D)
Hence, we can use the equation
to find the length of the side of a square.
What is the question I will just but dumb random facts
True facts
1.) it is fall
2.) my phone is at 51% omg
False facts
1.) cats have 9 lives
2.) I am 7 foot tall
Since this is a combination not a permutation problem, (order does not matter) you should use the "n choose k" formula.
C=n!/(k!(n-k)!) where C is the number of unique combinations, n equals the total number of possible choices and k equals the specific number of choices. In this case:
C=9!/(4!(9-4)!)
C=9!/(4!5!)
C=362880/(24*120)
C=362880/2880
C=126
So there are 126 unique ways to pick 4 people from a group of 9 people.
Answer: 3
Step-by-step explanation: There can be none, one, or infinite solutions. Therefore there can be up to three possible solutions to an inequality.
The answer is d he traveled 198 miles over the span of 12 months driving to his friends house.