Answer:
The equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

Step-by-step explanation:
Given
Point-Slope Form equation is








Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

I actually posted this a while ago and it got answerd by a smart person so here's what I understood
the error is that it assumes that √(x²)=x
because if x is negative, it becomes positive
that's how the 2nd line is wrong
the 2nd line is the first wrong step
it goes from 4-9/2+9/2
so it goes from 4-4.5+4.5
notice the part under the parenthsees
√((4-4.5)²)
if we evaluate 4-4.5, we get -0.5
but by squaring it we get 0.5
-0.5+4.5=4, yes
but when we square it we get
0.5+4.5=5, that is how it works
ANSWER

EXPLANATION
Part a)
Eliminating the parameter:
The parametric equation is


From the first equation we make t the subject to get;


We put it into the second equation.


We differentiate to get;

At x=5,


The slope of the tangent is 2.
The equation of the tangent through
(5,6) is given by




Without eliminating the parameter,



At x=5,



This implies that,

The slope of the tangent is 2.
The equation of the tangent through
(5,6) is given by



Answer:
∠z is 79°
Step-by-step explanation: