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nignag [31]
2 years ago
6

Calculate the circumference and area of this circle. 4cm radius​

Mathematics
2 answers:
BigorU [14]2 years ago
7 0

Answer: Using the formula,

Area=π×r2.

Area=π×r2.

=π×(4 cm)2.

=16π cm2≈50.24 cm2.

Step-by-step explanation:

Alja [10]2 years ago
5 0

Answer:

the circumference is 25.133 and the area is 50.265

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At the school carnival 14 out of 56 tickets sold where early admission tickets. What percentage of the ticket or early admission
cestrela7 [59]

Step-by-step explanation:

14/56×100=25%

14 early admission tickets/total tickets×100= percentage of early admission tickets

H

8 0
2 years ago
There are 3 people at a party. If each person must shake hands with every other person at the party exactly once, how many hands
Dima020 [189]
<h2>Answer:</h2>

The total number of handshakes that would happen between the three people are:

                                    3

<h2>Step-by-step explanation:</h2>

There are three people at a party.

Let they be denoted by A,B and C.

Now, the total number of handshakes that would occur will be denoted by:

      AB, AC and BC

where AB denotes that A and B shake hands.

AC denote that A and C shake hands.

and BC denote that B and C shake hands.

Hence, total number of handshakes are:

                           3

5 0
2 years ago
Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)
USPshnik [31]

\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k

\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k

\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5

Then the length of the arc is

\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi

4 0
3 years ago
1. Find the value of
spin [16.1K]

9514 1404 393

Answer:

  1. -√5
  2. 3/5
  3. -4/5

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

  cos = 1/sec

  csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

8 0
2 years ago
PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!
Llana [10]

Define your two QUESTIONS

Write your system of EQUATIONS

SOLVE the system of equations.

Find the SOLUTION to the question being asked.

6 0
2 years ago
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