I'm pretty sure you can just use a Cartesian plane and since all of your points are (positive, positive) they'd all be in the First Quadrant (top right)
For a perfect square
b² = 4*a*c
Comparing ax² + bx + c = 0 to x² + bx + 16
a = 1, c = 16
<span>b² = 4*a*c
</span>
<span>b² = 4*1*16
</span>
<span>b² = 64
</span>
b = √64
b = 8
The value of b = 8.
Angle m∠1 if formed by a tangent and secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)
Answer: m∠1=1/2(mJK-KL)
-5x-6.5>12
Add 6.5 to both sides...
-5x>18.5
Divide both sides by -5 and flip the sign...
x<-3.7
X=-1
-1x2 + 5x-1 +7 = 0
-7+7 =0
0=0
