Answer:
Component form : (-7 , 2)
Step-by-step explanation:
P(4 , 5) = P'(4 +x , 5+y) = P'(-3 , 7)
4 + x = -3
x = -3 - 4
x = -7
5 + y = 7
y = 7 - 5
y = 2
Vector form : -7i + 2j
Component form : (-7 , 2)
The ratio here is
3/4 cup milk 6 cups milk
-------------------- Now equate this to -----------------
1 beaten egg x
Solving this equation, (3/4)x = 6, and x = 8 (eggs) (answer)
Check: Note that 3/4 / 1 = 6 / 8
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hope this helps :)
Answer:
Present value = $4,122.4
Accumulated amount = $4,742
Step-by-step explanation:
Data provided in the question:
Amount at the Start of money flow = $1,000
Increase in amount is exponentially at the rate of 5% per year
Time = 4 years
Interest rate = 3.5% compounded continuously
Now,
Accumulated Value of the money flow = 
The present value of the money flow = 
= 
= ![1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4](https://tex.z-dn.net/?f=1000%5Cleft%20%5B%5Cfrac%7Be%5E%7B0.015t%7D%7D%7B0.015%7D%20%5Cright%20%5D_0%5E4)
= ![1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]](https://tex.z-dn.net/?f=1000%5Ctimes%5Cleft%20%5B%5Cfrac%7Be%5E%7B0.015%284%29%7D%7D%7B0.015%7D%20-%5Cfrac%7Be%5E%7B0.015%280%29%7D%7D%7B0.015%7D%20%5Cright%5D)
= 1000 × [70.7891 - 66.6667]
= $4,122.4
Accumulated interest = 
= 
= $4,742