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BartSMP [9]
3 years ago
5

Someone help me, will be giving brainliest, thanks. this is due today. just one question.

Mathematics
1 answer:
Inessa [10]3 years ago
3 0

Answer:

8,-6

Step-by-step explanation:

x^2 -6x +8 = 0

(x-4)(x-2)

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___ tens 15 ones = 6 tens 5 ones
Bezzdna [24]
The answer would be 5 tens.
4 0
3 years ago
Read 2 more answers
Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm
Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 6, \sigma = 0.2

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

Z = 0

Z = 0 has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 5.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

Z = -5

Z = -5 has a pvalue of 0.

1 - 0 = 1

5 0
3 years ago
What is the value of the function at x=−3?<br><br> A) y = 0<br> B) y=−3<br> C) y = 4<br> D) y = 3
Alexus [3.1K]

Answer:

y=4

Step-by-step explanation:

From the graph we can see that-

when, x=-3 ,  y=4

That is , the graph passes through   (-3 , 4)

So,

for  x=-3 ,

we get    y=4

So, the answer is    y=4

5 0
3 years ago
PLEASE HELP ASAP!!!!!!
Katena32 [7]
1. - Since a cube is all the same lengths on all sides you would want to find the area of one of the sides. You would do this by multiplying 3.8 by 3.8.
3.8*3.8=14.44
Since you have six faces on a cube you want to multiply this by 6.
14.44*6=86.64
So your answer for 1. is 86.64 in^2 of glass

3. Same thing as number one. Find the face of one side:
1 1/3*1 1/3 is about 1.7777
Multiply this by the six faces. 
1.7777*6 is about 10.66666
So your answer for 3. is about 10.666 (repeating) in^2

4. For this one, you want to follow the surface area formula for a cylinder. Which is - A=2πrh+2πr^2
When you put all your numbers in it would look like this: 
2*3.14*2*22+2*3.14*2^2
Once you do that equation you will get 301.44
So that should be your answer 301.44 cm^2

Hope this helps!
8 0
3 years ago
What values of x makes the expression (x-6)(x+3) positive?​
Georgia [21]

Answer:

This means that for (x-6)(x+3) to be positive, the value of x has to be greater than 6; x>6

Step-by-step explanation:

Step 1

Given the equation;

(x-6)(x+3)

Step 2

To determine the values of x that make the equation positive, the equation can be expressed as;

(x-6)(x+3)>0

x-6>0/(x+3)

x-6>0

x>0+6

x>6

This means that for (x-6)(x+3) to be positive, the value of x has to be greater than 6; x>6

4 0
3 years ago
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