Answer:
54.8 feet
Step-by-step explanation:
We assume that the distance of interest is the direct line distance from the observation point to the bottom of the monument, segment PH in the diagram below.
This can be found using the Law of Sines.
∠PMH is the complement of the angle of elevation to the top of the monument, so is 40°.
∠MPH is the difference in the angles of elevation, so is 28°.
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The Law of Sines tells us the ratio of side lengths is the same as the ratio of the sines of the opposite angles, so ...
PH/MH = sin(∠PMH)/sin(∠MPH) = sin(40°)/sin(28°)
Multiplying by MH, we can find the length of PH:
PH = (40 ft)(sin(40°)/sin(28°)) ≈ 54.7669 ft
PH ≈ 54.8 ft . . . . the distance Pete must climb to reach the monument.
2(x + 5) = 40 ....................
Hi!
The set up for the question is like this:
Hope this helps!
Answer:
- high tide occurs at 12 noon and 12 midnight
- Low tide occurs at 6 a.m and 6 p.m
- maximum depth value = 20 ft
- Minimum depth value = 15 ft
Step-by-step explanation:
The depth is modelled as;
y = 20 + 5 cos (πt/6)
We are told that t = 0 represents 12:00 midnight.
This is high tide because at t = 0, the cos function will be at it's maximum value of 1 since cos 0 = 1.
Max depth value is;
y = 20 + 5(0)
y = 20 ft
Minimum depth value will be the low tide and it will be when the cos function is equal to -1.
Thus;
y = 20 + 5(-1)
y = 15 ft
Since t represents number of hours and since at 12 midnight, t = 0, thus; high tide will occur again at;
12 noon
Also, let's check for low tide.
Let's try t = 6 which means 6 a.m
Thus;
y = 20 + 5 cos (π(6)/6)
y = 20 + 5 cos π
Cos π has a value of -1
Thus;
y = 20 + 5(-1)
y = 20 - 5
y = 15 ft
Thus;
Low tide occurs at 6 a.m and 6 p.m
The correct answers for this completion exercise are the option "B" and the option "C":
B. cm³
C. cc
This means that you can write the unit of volume (or capacity) cm³ as cc.
Therefore, cm³=cc
For example, you have:
a) 10 cm³=10 cc
b) 110 cc=110 cm³
c) 1 litre (l)=1000 cm³
d) 1 litre (l)=1000 cc
