Answer:
The product of given matrix is 
Step-by-step explanation:
Given : Two matrix
and 
We have to find the product of given matrix
Multiply the rows of first matrix by the columns of second matrix , we have,
On , simplifying , we get,
Thus, the product of given matrix is
The Leading Coefficient Of The Polynomial Is -6
The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
brainly.com/question/24369824
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The expression to go with the words is 2x6-9
let's say that C is "x" units farther from B, that means that CB = x, and therefore AC = 1.5x.
![\bf \underset{\leftarrow ~~30~~\to}{\boxed{A}\stackrel{1.5x}{\rule[0.35em]{18em}{0.25pt}}C\stackrel{x}{\rule[0.35em]{10em}{0.25pt}}\boxed{B}} \\\\\\ AB=AC+CB\implies \stackrel{AB}{30}=\stackrel{AC}{1.5x}+\stackrel{CB}{x}\implies 30=2.5x \\\\\\ \cfrac{30}{2.5}=x\implies 12=x \\\\[-0.35em] ~\dotfill\\\\ AC=1.5(12)\implies AC=18~\hspace{8em} CB=x\implies CB=12](https://tex.z-dn.net/?f=%5Cbf%20%5Cunderset%7B%5Cleftarrow%20~~30~~%5Cto%7D%7B%5Cboxed%7BA%7D%5Cstackrel%7B1.5x%7D%7B%5Crule%5B0.35em%5D%7B18em%7D%7B0.25pt%7D%7DC%5Cstackrel%7Bx%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%5Cboxed%7BB%7D%7D%0A%5C%5C%5C%5C%5C%5C%0AAB%3DAC%2BCB%5Cimplies%20%5Cstackrel%7BAB%7D%7B30%7D%3D%5Cstackrel%7BAC%7D%7B1.5x%7D%2B%5Cstackrel%7BCB%7D%7Bx%7D%5Cimplies%2030%3D2.5x%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B30%7D%7B2.5%7D%3Dx%5Cimplies%2012%3Dx%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0AAC%3D1.5%2812%29%5Cimplies%20AC%3D18~%5Chspace%7B8em%7D%20CB%3Dx%5Cimplies%20CB%3D12)
