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3 years ago

Help me please please help me

Mathematics

2 answers:

hjlf3 years ago

6 0

Answer:

7.5

Step-by-step explanation:

So 7 r 1

BARSIC [14]3 years ago

4 0

Answer:

7 r 1

Step-by-step explanation:

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Solve for x 11^x/11^3=11^2 PPEASE I HAVE AN F

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3 years ago

Complete the table for the following function<br> y=(1/3)^x

Bumek [7]

x=-3 then y= 27

x= -2 then y= 9

x=2 then y: $y=\frac{1}{9}$

x=3 then y: $y=\frac{1}{27}$

The graph of the function decreases from left to right.

Option C is correct.

Step-by-step explanation:

We are given the function: $y=(\frac{1}{3})^x$

and we need to fill the table

if x = -3 then y=?

Putting value of x in the given function:

$y=(\frac{1}{3})^x$

$y=(\frac{1}{3})^-3$

Applying exponent rule a^-b= 1/a^b

$y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{\frac{1}{27}}\\y=27$

if x = -2 then y=?

Putting value of x in the given function:

$y=(\frac{1}{3})^x$

$y=(\frac{1}{3})^-2$

Applying exponent rule a^-b= 1/a^b

$y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{\frac{1}{9}}\\y=9$

if x = 2 then y=?

Putting value of x in the given function:

$y=(\frac{1}{3})^x$

$y=(\frac{1}{3})^2$

Applying exponent rule a^-b= 1/a^b

$y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{9}$

if x = 3 then y=?

Putting value of x in the given function:

$y=(\frac{1}{3})^x$

$y=(\frac{1}{3})^3$

Applying exponent rule a^-b= 1/a^b

$y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{27}$

So, x=-3 then y= 27

x= -2 then y= 9

x=2 then y: $y=\frac{1}{9}$

x=3 then y: $y=\frac{1}{27}$

Graph of the function is shown in figure attached.

The graph of the function decreases from left to right.

Option C is correct.

Keywords: Solving Equations

Learn more about Solving Equations at:

#learnwithBrainly

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3 years ago

Orders of operations

frosja888 [35]

Answer:

PEMDAS

Step-by-step explanation:

First you do the numbers in the parentheses and the exponents

Then you do any multiplication or division in the problem.

Finally, you do any addition or subtraction in the problem.

*All of this should be done from left to right

4 0

4 years ago

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