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faltersainse [42]
3 years ago
10

Question 15 of 20 Which model could represent a neutral atom of nitrogen?

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
4 0
The picture is black
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An alkyne with the molecular formula C5H8 was reduced with H2 and Lindlar's catalyst. Hydroboration-oxidation of the resulting a
irinina [24]

Since the addition of the H2O in the last step of hydroboration is anti-Markovnikov, the starting material is 1-pentyne.

The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.

When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.

Learn more: brainly.com/question/2510654

6 0
3 years ago
Calculate the standard enthalpy of formation of carbon disulfide (CS2) from it's elements, given that C(graphite) + O2(g) → CO2(
ch4aika [34]

Answer:

Standard enthalpy of formation of Carbon disulfide CS2 = 87.3 KJ/mol

Explanation:

forming CS2 means that it should in the product side

C(graphite) + O2 → CO2                  ΔH = -393.5

2S(rhombic) + 2O2 → 2SO2            ΔH = -296.4 x 2

CO2 + 2SO2 → CS2 + 3O2             ΔH = -1073.6 x -1

the second reaction is multiplied by 2 so that the SO2 and O2 can cancel out.

the third reaction is reversed (multiplied by -1) so that CS2 will be on the product side.

after adding the reaction and cancelling out similarities, the final reaction is: C(graphite) + 2S(rhombic) → CS2

Add ΔH to find the enthalpy of formation of CS2

ΔHf = (-393.5) + (-296.4 x 2) + (-1073.6 x -1) = 87.3 KJ/mol

be aware of signs

3 0
3 years ago
Which example best shows that the chemistry of water is helpful to plants
kenny6666 [7]
<span>Water's polarity causes cohesion that pulls other water molecules up through a plant.</span>
4 0
4 years ago
Read 2 more answers
Lithium diisopropylamide [(CH3)2CH]2NLi, referred to as LDA, enjoys many uses as a strong base in synthetic organic chemistry. I
meriva

Answer:

Lithium diisopropylamide [(CH3)2CH]2NLi.

Explanation:

Lithium diisopropylamide (commonly abbreviated LDA) is a chemical compound with the molecular formula [(CH3)2CH]2NLi. It is used as a strong base and has been widely accepted due to its good solubility in non-polar organic solvents and non-nucleophilic nature. It is a colorless solid, but is usually generated and observed only in solution. It was first prepared by Hamell and Levine in 1950 along with several other hindered lithium diorganylamides to effect the deprotonation of esters at the α position without attack of the carbonyl group.

5 0
3 years ago
Help me please asap ...........................................
lianna [129]
3. The Chemical property of an unknown element is the number of valence electrons
4. The number of protons in one atom of an element
Hope I helped :))
6 0
3 years ago
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