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SVETLANKA909090 [29]
2 years ago
13

quizlet a basement is successfully sealed so that more radon may not enter the space, but 5.7×107 radon atoms are already trappe

d. how many radon atoms remain after 25 days?
Chemistry
1 answer:
12345 [234]2 years ago
6 0

After 25 days, it remains radon 5.9x10^5 atoms.

Half-life is the time required for a quantity (in this example number of radioactive radon) to reduce to half its initial value.

N(Ra) = 5.7×10^7; initial number of radon atoms

t1/2(Ra) = 3.8 days; the half-life of the radon is 3.8 days

n = 25 days / 3.8 days

n = 6.58; number of half-lifes of radon

N1(Ra) = N(Ra) x (1/2)^n

N1(Ra) = 5.7×10^7 x (1/2)^6.58

N1(Ra) = 5.9x10^5; number of radon atoms after 25 days

The half-life is independent of initial concentration (size of the sample).

More about half-life: brainly.com/question/1160651

#SPJ4

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3 0
3 years ago
Determine the location of the last significant place value by placing a bar over the digit.
Vlad1618 [11]

Answer:

8,040  

0.0300  

699.5  

2.000 x 102

0.90100  

90, 100  

4.7 x 10-8  

10,800,000.0  

3.01 x 1021

0.000410

Explanation:

First remember the following rules of determining the last significant place value :

1. The digits from 1-9 are all significant and zeros between significant digits are also significant.

2.  The trailing or ending zeroes are significant only in case of a decimal number otherwise they are ignored. However starting zeroes of such a number are not significant.

Now observing above rules, lets determine the location of the last significant place value of each given example. I am determining the location by turning the last significant place to bold.

1) 8,040

8,040

Location of the last significant place value is 3 and bar is over last significant digit that is 4. Number is not decimal so ending zero is ignored. Every non zero digit is a significant.

2)  0.0300

0.0300

Location is 3 and bar is over 0. Number has a decimal point so ending zero is not ignored but starting zeroes are ignored.

3) 699.5

699.5

Location is 4 and bar is over 5.

4) 2.000 x 10²

2.000 x 10²

Location is 4 and bar is over 0. This is because the number is decimal so trailing zeroes cannot be ignored. Also if we convert this number it becomes:

200.0 so last significant digit is 0 and location of last significant digit is 4.

5) 0.90100

0.90100

Location is 5 and bar is over 0. This is because in a number with decimal point starting zeroes are ignored but trailing zeroes after decimal point are not ignored. So we count from 9 and last significant digit is 0.

6) 90, 100

90, 100

Location is 3 and bar is over 1. This is because it is not a number with decimal point. So the trailing zeroes are ignored. The count starts from 9 and last significant is 1.

7) 4.7 x 10⁻⁸

4.7 x 10⁻⁸

Location is 2 and bar is over 7. This is because the starting zeroes in a number with a decimal point are ignored. So the first digit considered is 4 and last significant digit is 7. If we expand this number:

4.7 x 10⁻⁸ =    0.000000047 = 0.000000047

Here the starting zeroes are ignored because there is a decimal point in the number.

8) 10,800,000.0

10,800,000.0

Location is 9 and bar is over 0.  Number has a decimal point so ending zero is not ignored and last significant figure is 0.

However if the number is like:

10,800,000. Then location would be 8 and bar is over 0.

9) 3.01 x 10²¹

3.01 x 10²¹

Location is 3 and bar is over 1. Lets expand this number first

3.01 x 10²¹ = 3.01 x 1000000000000000000000

                  = 3010000000000000000000

So this is the number:

3010000000000000000000

Since this is number does not have a decimal point so the trailing zeroes are ignored. Hence the count starts from 3 and the last significant figure is 1

10) 0.000410

0.000410

Location is 3 and bar is over 0. This is because the number has a decimal point so the ending zero is not ignored but the starting zeroes are ignored according to the rules given above. Hence the first significant figure is 4 and last significant figure is 0.

6 0
3 years ago
Hello Friends! think you guys can help a sister out lol > Based on the following image, what is the chemical formula of the c
kiruha [24]

Answer:

CO_2

Explanation:

Looking at the atom, you see that there is 1 carbon atom and 2 oxygen atoms.

The chemical formula of Carbon is just C (from the periodic table), and the chemical formula of Oxygen is just O (from the periodic table).

When you create the chemical formula of a compound, you want to indicate how many atoms of each element there are. Here, since there are 2 oxygen atoms, you want to have some form of O_2 , and since there's only 1 carbon atom, you want to have some form of C.

Now, we just put it together: CO_2 (this is btw carbon dioxide)

Hope this helps!

3 0
4 years ago
The formula for acetic acid is CH3COOH(aq). How many of each type of atom are there in this molecule?
miss Akunina [59]
C) is the right answer
5 0
4 years ago
Determine the amount in grams of kcl that exists in 20.3 g of a solution that contains 1.14 % KCI by mass.
artcher [175]

Answer:

0.23 g

Explanation:

From the question given above, the following data were obtained:

Mass of solution = 20.3 g

Percentage by mass of KCl = 1.14%

Mass of KCl =?

The mass of KCl in the solution can be obtained as follow:

Percentage by mass = mass of solute / mass of solution × 100

1.14% = mass of KCl / 20.3

Cross multiply

Mass of KCl = 1.14% × 20.3

Mass of KCl = 1.14/100 × 20.3

Mass of KCl = 0.0114 × 20.3

Mass of KCl = 0.23 g

Therefore, the mass of KCl in the solution is 0.23 g

6 0
3 years ago
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