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Alex17521 [72]
3 years ago
7

A common function of proteins and carbohydrates in the plasma membrane is...

Chemistry
1 answer:
Vika [28.1K]3 years ago
8 0
I believe your answer is B.
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Individual measurements introduce errors that may be large or small depending on the quality of the tools and processes used. Sc
kirill [66]

Answer:

B. accepted value x 0.1

Explanation:

in the equation provided

Percentage Error=\frac{Error}{AcceptedValue} X100

Maximum allowed value of percentage error = 10%

put this value in the equation in stead of percentage error we get,

10 = \frac{error}{AcceptedValue} X100\\ \frac{10}{100} =\frac{error}{AcceptedValue}\\.1=\frac{error}{AcceptedValue}\\error = .1 X Accepted Value

so maximum error = .1 x accepted value

10 % percentage error means the experimental value has 10 % error compared to accepted value.so error will be 10 % of the accepted value

or .1 times of accepted value

8 0
3 years ago
HELP PLEASE 100 points!!!
djyliett [7]

Answer:

by the looks of it the answer you have is correct

Explanation:

3 0
2 years ago
Read 2 more answers
What is the frequency of a radio wave with a a wavelength of 3 m? (Hint: MHz
Ostrovityanka [42]

Answer:
a. 1 x 10^8

Explanation:

100 MHz = 100,000,000 Hz = 10^8 Hz

4 0
2 years ago
A substance composed of two or more elements in a fixed, definite proportion is.
Arisa [49]

Answer:

Compound

Explanation:

-compound is a chemical substance composed of many identical molecules composed of atoms from more than one element held together by chemical bonds.

7 0
2 years ago
Read 2 more answers
A sample of O2 with an initial temperature of 50.0 oC and a volume of 105 L is cooled to -25 oC. The new pressure is 105.4 kPa a
Damm [24]

Answer:

71.92 kPa

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

T1 = 50°C = 50 + 273 = 323K

V1 = 105L

T2 = -25°C = -25 + 273 = 248K

P2 = 105.4 kPa

P1 = ?

V2 = 55.0 L

Using P1V1/T1 = P2V2/T2

P1 × 105/323 = 105.4 × 55/248

105P1/323 = 5797/248

0.325P1 = 23.375

P1 = 23.375 ÷ 0.325

P1 = 71.92 kPa

4 0
3 years ago
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