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Nadusha1986 [10]
3 years ago
5

How many grams are in 2.3 moles of N?

Chemistry
2 answers:
jok3333 [9.3K]3 years ago
6 0
The amount of grams that are in 2.3 moles of N = 32.223 or 32/100
Because there are 14.01 grams per mile of nitrogen atoms.
So…
14.01 x 2.3= 32.223
Hope this helps :)
Lina20 [59]3 years ago
3 0

Answer:

Therefore, 40.4 grams are contained in 2 moles of Neon.

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What is number 1 for b, c, and d?
SVETLANKA909090 [29]
B because....................
4 0
3 years ago
The volume of a sample of <img src="https://tex.z-dn.net/?f=P_b" id="TexFormula1" title="P_b" alt="P_b" align="absmiddle" class=
murzikaleks [220]

Answer : The mass of sample is, 267.5 grams.

Explanation :

Density : It is defined as the mass of a substance contained per unit volume.

Formula used :

Density=\frac{Mass}{Volume}

Given:

Volume of Pb = 23.57cm^3

Density of Pb = 11.35g/cm^3

Now put all the given values in the above formula, we get the mass of Pb.

11.35g/cm^3=\frac{Mass}{23.57cm^3}

Mass=267.5195g=267.5g

Therefore, the mass of sample is, 267.5 grams.

5 0
3 years ago
An electron in the hydrogen atom makes a transition from an energy state of principal quantum number ni to the n = 2 state. If t
topjm [15]

Answer:

\boxed{3}

Explanation:

The Rydberg equation gives the wavelength λ for the transitions:

\dfrac{1}{\lambda} = R \left ( \dfrac{1}{n_{i}^{2}} - \dfrac{1}{n_{f}^{2}} \right )

where

R= the Rydberg constant (1.0974 ×10⁷ m⁻¹) and

\text{$n_{i}$ and $n_{f}$ are the numbers of the energy levels}

Data:

n_{f} = 2

λ = 657 nm

Calculation:  

\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}

7 0
3 years ago
Draw the structure of the major organic product isolated from the reaction of 1-hexyne with sodium amide in liquid ammonia follo
77julia77 [94]

Answer:check explanation and attached file/picture

Explanation:

Alkynes are hydrocarbons and they are very acidic because of hybridization effect(the more acidic the s-character is, the more acidic it is going to be).

The reaction of 1-hexyne with sodium amide in liquid ammonia is a form of deprotonation 'reaction' to form acetylide. Due to the acidic nature of the terminal hydrogen atom, terminal alkynes do form metallic derivatives by the replacement of the terminal hydrogens. The equation of Reaction is given below.

C6H10 + NaNH2( in liquidNH3) ------------> C6H9Na + H-NH2.

The acetylide is a bae and a very good nucleophile.

The reaction is then followed by the addition of 1-bromobutane. This reaction is used for the production of longer chain alkynes. The equation of Reaction is attached in the picture.

3 0
3 years ago
Read 2 more answers
Rank the effective nuclear charge Z* experienced by a valence electron in each of these atoms:
LekaFEV [45]

Answer:

The atoms are ranked in decreasing order as follows:

Fluorine ---4

Carbon ----3

Boron ------2

Beryllium --1

Explanation:

Effective nuclear charge (Zeff) is defined as the difference between the actual nuclear charge (the atomic number, Z) and the shielding constant (S).

It is calculated by finding the atomic number and electronic configuration, attributing a shielding value to each electron, adding all the shielding values and using the formula:

                 Z eff = Z - S

Effective nuclear charges:

An atom of carbon: 3.25

An atom of fluorine: 5.20

An atom of beryllium: 1.95

An atom of boron: 2.60

5 0
3 years ago
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