Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
g = 2H/(m + r)
Step-by-step explanation:
mg + rg = 2H
g(m + r) = 2H
(g(m + r))/(m + r) = 2H/(m + r)
g = 2H/(m + r)
X-5) = 2(x-1)
3x-15 = 2x - 2
x - 15 = -2
x = 13
It's a simple linear equation in 'n'. There's only one number that 'n' can be
that will make the equation a true statement. That number is called the
'solution' to the equation. Here's one way to find it:
You said that <u> -7n - 4 = 24</u>
Add 4 to each side: -7n = 28
Multiply each side by -1 : 7n = -28
Divide each side by 7 : <em>n = -4</em>
Homework is the only way for most people to learn stuff.
Answer:
I believe it would be true
