Volume of the cone = 56.52 in³
Solution:
Diameter of the cone = 6 in
Radius of the cone = 6 ÷ 2 = 3 in
Height of the cone = 6 in
The value of π = 3.14
<u>To find the volume of the cone:</u>
Volume of the cone = 
= 56.52
Volume of the cone = 56.52 in³
Hence the volume of the given cone is 56.52 
.
Answer:
number 1 is b
Step-by-step explanation:
7x20=140. 7x2000=14000. The only thing that changes the product of these numbers is the amount of zeros behind the 2. Since the only two numbers that affect the answer is the 7 and the 2. (7x2=14). The number of zeros behind the 2 affect how many zeros will be included in the product.
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
