May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Answer:
3000
Step-by-step explanation:
Answer:
x = 6
Step-by-step explanation:
Givens
There are 3 sides. All are equal to (4x - 3)
Their sum = 63
Formula
3(4x - 3) = 63
Solution
- 3(4x - 3) = 63 Divide by 3
- 12x - 9 = 63 Add 9 to both sides
- 12x = 63 + 9
- 12x = 72 Divide by 12
- x = 72/12
x = 6 Answer
To write an improper fraction a mixed number you start by seeing how many times the denominator (bottom number) goes in to the numerator (top number). Since the denominator is 9 and the numerator is 29, 9 goes into 29 3 times. The left over numbers become the fraction of which is in simplest form.
<em>3 x 9 = 27</em>
<em>29 - 27 = 2</em>
<u>Mixed number: 3 2/9</u>
the answer is 5. hope this helps
Pls mark as brainliest
