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dybincka [34]
3 years ago
15

Problem ID: PRABJVTY

Mathematics
1 answer:
aksik [14]3 years ago
3 0

Answer:

I'm confused too I'm sorry

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Find the perimeter of the figure to the nearest hundredth.<br> Please consider helping!
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I believe it is 103m
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Reuben has scores of 70,75,83, and 80 on four spanish quizzes. what score must he get on the next quiz to achieve an average of
Sergio [31]
X - the score he must get

\frac{70+75+83+80+x}{5} \geq 80 \\&#10;\frac{308+x}{5} \geq 80 \\&#10;308+x \geq 400 \\&#10;x \geq 92

He must get at least 92 points.
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What’s the answer to this question?
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b

Step-by-step explanation:

8 0
3 years ago
Beatrice built about 1/3 of a sandcastle. Linda built 4/7 of the same castle. What fraction of the sandcastle did they build tog
wlad13 [49]

Answer    

Find out the what fraction of the sandcastle did they build together .

To prove

Let us assume that the fraction of the sandcastle  they build together be x .

As given

Beatrice\ built\ about\ \frac{1}{3}\ of\ a\ sandcastle.

Linda\ built\ \frac{4}{7}\ of\ the\ same\ castle.

Than the equation becomes

x = \frac{1}{3} +\frac{4}{7}

L.C .M of (3,7) = 21

solving

x = \frac{7 + 3\times4}{21}

x = \frac{19}{21}

Therefore the fraction of the sandcastle did they build together be

x = \frac{19}{21}

Hence proved



4 0
3 years ago
In a recently administered iq test, the scores were distributed normally, with mean 100 and standard deviation 15. what proporti
iragen [17]

To solve for proportion we make use of the z statistic. The procedure is to solve for the value of the z score and then locate for the proportion using the standard distribution tables. The formula for z score is:

z = (X – μ) / σ

where X is the sample value, μ is the mean value and σ is the standard deviation

 

when X = 70

z1 = (70 – 100) / 15 = -2

Using the standard distribution tables, proportion is P1 = 0.0228

 

when X = 130

z2 = (130 – 100) /15 = 2

Using the standard distribution tables, proportion is P2 = 0.9772

 

Therefore the proportion between X of 70 and 130 is:

P (70<X<130) = P2 – P1

P (70<X<130) = 0.9772 - 0.0228

P (70<X<130) = 0.9544

 

Therefore 0.9544 or 95.44% of the test takers scored between 70 and 130.

6 0
3 years ago
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