3.6 * 10^(-3) is the scientific notation
Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
Answer:
Step-by-step explanation:
- Number of dimes = d, each d = 10 c
- Number of quarters = q, each q = 25 c
- Total = $2 = 200 c
<u>Equations according the given:</u>
<u>Solve for q by substitution:</u>
- 10(q + 6) + 25q = 200
- 10q + 60 + 25q = 200
- 35q = 140
- q = 140/35
- q = 4
<u>Find the value of d:</u>
Nathaniel has 10 dimes and 4 quarters
X + (4x+15) = 180
5x+15=180
5x=165
x=33
4(33)+15=147. (Or you could subtract 33 from 180)
Check answer: 33+147=180 yes
